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frosja888 [35]
3 years ago
10

Find the seventh term of the sequence given by the rule t = -5n+2

Mathematics
1 answer:
Artemon [7]3 years ago
6 0
I would go with -33 cause if you replace the t with -33 you would have to solve the problem and it would be 7 so -33 is the answer.
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Between 1-50 what number are composite?
mash [69]
4,6,8,9,10,12,14,15,16,18,20,21,22,24,25,26,27,28,30,32,33,34,35,36,38,39,40,42,44,45,46,48,49,And 50!
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3 years ago
You are putting a fence around a square outdoor stage with an area of 289 square feet. What is the length of one side of the sta
nikdorinn [45]
17 because the square root of 289 is 17
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3 years ago
Find the sum of the first 25 terms in this geometric series:<br> 8 + 6 + 4.5...
Ksivusya [100]

Step-by-step explanation:

Given the geometric sequence

8 + 6 + 4.5...

A geometric sequence has a constant ratio and is defined by

a_n=a_1\cdot r^{n-1}

\mathrm{Compute\:the\:ratios\:of\:all\:the\:adjacent\:terms}:\quad \:r=\frac{a_{n+1}}{a_n}

\frac{6}{8}=\frac{3}{4},\:\quad \frac{4.5}{6}=\frac{3}{4}

\mathrm{The\:ratio\:of\:all\:the\:adjacent\:terms\:is\:the\:same\:and\:equal\:to}

r=\frac{3}{4}

\mathrm{The\:first\:element\:of\:the\:sequence\:is}

a_1=8

\mathrm{Therefore,\:the\:}n\mathrm{th\:term\:is\:computed\:by}\:

a_n=8\left(\frac{3}{4}\right)^{n-1}

\mathrm{Geometric\:sequence\:sum\:formula:}

a_1\frac{1-r^n}{1-r}

\mathrm{Plug\:in\:the\:values:}

n=25,\:\spacea_1=8,\:\spacer=\frac{3}{4}

=8\cdot \frac{1-\left(\frac{3}{4}\right)^{25}}{1-\frac{3}{4}}

\mathrm{Multiply\:fractions}:\quad \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}

=\frac{\left(1-\left(\frac{3}{4}\right)^{25}\right)\cdot \:8}{1-\frac{3}{4}}

=\frac{8\left(-\left(\frac{3}{4}\right)^{25}+1\right)}{\frac{1}{4}}

\mathrm{Apply\:exponent\:rule}:\quad \left(\frac{a}{b}\right)^c=\frac{a^c}{b^c}

=\frac{8\left(-\frac{3^{25}}{4^{25}}+1\right)}{\frac{1}{4}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}

=\frac{\left(1-\frac{3^{25}}{4^{25}}\right)\cdot \:8\cdot \:4}{1}

\mathrm{Multiply\:the\:numbers:}\:8\cdot \:4=32

=\frac{32\left(-\frac{3^{25}}{4^{25}}+1\right)}{1}

=\frac{32\cdot \frac{4^{25}-3^{25}}{4^{25}}}{1}               ∵ \mathrm{Join}\:1-\frac{3^{25}}{4^{25}}:\quad \frac{4^{25}-3^{25}}{4^{25}}

=32\cdot \frac{4^{25}-3^{25}}{4^{25}}

=\frac{\left(4^{25}-3^{25}\right)\cdot \:32}{4^{25}}

=\frac{2^5\left(4^{25}-3^{25}\right)}{2^{50}}        ∵ \mathrm{Factor}\:32:\ 2^5,  \mathrm{Factor}\:4^{25}:\ 2^{50}

so

=\frac{4^{25}-3^{25}}{2^{45}}        ∵ \mathrm{Cancel\:}\frac{\left(4^{25}-3^{25}\right)\cdot \:2^5}{2^{50}}:\quad \frac{4^{25}-3^{25}}{2^{45}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a\pm \:b}{c}=\frac{a}{c}\pm \frac{b}{c}

=\frac{4^{25}}{2^{45}}-\frac{3^{25}}{2^{45}}      

=32-\frac{3^{25}}{2^{45}}            ∵  \frac{4^{25}}{2^{45}}=32

=32-0.024        ∵  \frac{3^{25}}{2^{45}}=0.024

=31.98            

Therefore, the sum of the first 25 terms in this geometric series: 31.98

3 0
3 years ago
I’m not understanding the answer listed on this site to the following question:
kobusy [5.1K]
Okay, I think I understand this. Our first step is to solve how long the string is after he used some of it to tie the package. I have a feeling we have to subtract 7/8 - 1/5. Find a least common multiple (in this case, it's 40) and our new fractions are 35/40 and 8/45. Subtract:

35/40 - 8/40 = 27/40.

I don't think this can be simplified down any further as they do not have any common factors. So with that in mind, let's divide 27/40 with 5/1 (5/1 is basically 5 wholes but in fraction version)

When dividing fractions, you want to use the KCF technique (my old math teacher taught me this). Keep the first fraction the same (in this case, 27/40), change the sign from multiplication to division, and flip 5/1 to get it's reciprocal, 1/5. The equation will look like this:

27/40 * 1/5 = 27/200

So each piece is about 27/200 m in length (or 0.135 m in length).

If this is wrong, please let me know, but this is what I got out of this question. I hope this helped you :)
4 0
3 years ago
N(-2,-2) After a rotation 90 degrees counterclockwise
RUDIKE [14]

Answer: (2,-2)

Step-by-step explanation:

Rotating 90 degrees counterclockwise (about the origin) maps (x,y) onto (-y,x), so the answer is <u>N'(2,-2)</u>

6 0
2 years ago
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