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BabaBlast [244]
3 years ago
6

Divide. 38/733 Enter your answer in the boxes.

Mathematics
2 answers:
fenix001 [56]3 years ago
8 0

Answer: 0.051

Step-by-step explanation: Am very big brain, My IQ is above your comprehension.

Brut [27]3 years ago
8 0

Answer:

the answer is 0.051

Step-by-step explanation:

i did it

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15v − -14v − -14 = -15 solve for v ps..... help plz
Alchen [17]

Solve for  v  by simplifying both sides of the equation, then isolating the variable.

v = -1

5 0
3 years ago
Juan pulled a red card from the deck of regular playing cards. This probability is 2652 or 12 . He puts the card back into the d
kenny6666 [7]

Answer:

no

Step-by-step explanation:

if he randomly pulls it out it's still the same number of red cards and also the total number of cards as always

can't change

6 0
3 years ago
Read 2 more answers
I need to work out x
frutty [35]

Answer:

9,765 cm

Step-by-step explanation:

We'll solve out the measurements for triangle ABC then it will be easy to figure out x

For triangle ABC, we have

Angle B = 90 degrees.

Angle A (CAB) = 38 degrees (the angle CAD is 19 and is said to be half of CAB, since the line AD is a bisector).

Angle C = 180 - 90 - 38 = 52 degrees.

To find the measurement of the BC line, which we label a, we know that

\frac{a}{sin(A)} = \frac{c}{sin(c)}

So, we can isolate the a to get:

a = \frac{c * sin(A)}{sin(c)} = \frac{25 * sin(38)}{sin(52)} = 19.53

Now we know the segment BC is 19.53 cm.

And we know that segments CD and DB are equal, since AD is a bisector, cutting the CAB angle in half.

So, CD is half of BC.... so 19.53 / 2 = 9.765 cm

7 0
3 years ago
What is 6 1/10 plus 5 4/5 ASAP please
Virty [35]

Answer:

11 9/10

Step-by-step explanation:

6 + 5 = 11

1/10 + 4/5

1/10 + 8/10 = 9/10

11 + 9/10 = 11 9/10

HOPE THIS HELPS

PLZ MARK BRAINLIEST

5 0
3 years ago
Read 2 more answers
How do you verify this trigonometric identity? cos^2 θcot^2 θ = cot^2 θ - cos^2 θ
sattari [20]
<h3>Explanation:</h3>

Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).

  cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)

  (1 -sin^2(θ))cot^2(θ) =  . . . . . replace cos^2 with 1-sin^2

  cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin

  cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired

8 0
3 years ago
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