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Sindrei [870]
3 years ago
11

A school wants to build a rectangular playground that will have a diagonal length of 75 yards. How wide can the playground be if

the length has to be 30 yards?
Mathematics
1 answer:
Marianna [84]3 years ago
3 0
The answer would be 112 yards! It's simple because all you've got to do is use the Pythagorean Theorem! Oh! You should also go check out Socratic, it's a good app for this stuff!

~Hope this helped~
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Kellen got an e-mail from his bank on June 7th, June 21st, July 5th, and July 19th. Use inductive reasoning to predict the next
Alex Ar [27]

Answer:

August 2nd

Step-by-step explanation:

31 days in july, last email on the 19th

19-5=14

31-19=12

12+2=14

August 2nd, please mark brainliest

8 0
3 years ago
Read 2 more answers
Test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students at the 0.005 signif
algol [13]

Answer:

a) F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

b) B. two-tailed

d) t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

e) p_v =P(t_{118}  

f) B. Reject the null hypothesis

Step-by-step explanation:

Information provided

\bar X_{O}=2.91 represent the mean for the Orange Coast

\bar X_{C}=2.96 represent the mean for the Coastline

s_{O}=0.05 represent the sample standard deviation for Orange Coast

s_{C}=0.03 represent the sample standard deviation for Coastline

n_{O}=60 sample size for Orange Coast

n_{C}=60 sample size for Coastline

\alpha=0.005 Significance level provided

t would represent the statistic

Part a

For this case we want to test the claim that the mean GPA of Orange Coast students is smaller than the mean GPA of Coastline students

Null hypothesis:\mu_{O} \geq \mu_{C}  

Alternative hypothesis:\mu_{O} < \mu_{C}  

F. H 0 : μ O ≥ μ C

H 1 : μ O < μ C

Part b

For this case we need to conduct a left tailed test.

B. two-tailed

Part d

The statistic is given by:

t=\frac{(\bar X_{O}-\bar X_{C})-\Delta}{\sqrt{\frac{s^2_{O}}{n_{O}}+\frac{s^2_{C}}{n_{C}}}} (1)  

And the degrees of freedom are given by df=n_1 +n_2 -2=60+60-2=118  

Replacing the info we got:

t=\frac{(2.91-2.96)-0}{\sqrt{\frac{0.05^2}{60}+\frac{0.03^2}{60}}}}=-6.64  

Part e

We can calculate the p value with this probability:

p_v =P(t_{118}  

Part f

Since the p value is a very low value compared to the significance level given of 0.005 we can reject the null hypothesis.

B. Reject the null hypothesis

5 0
2 years ago
HELP PLEASE IM REALLY STUCK
liberstina [14]
The 15th term will be 71. Why? Well, see below for an explanation!

By subtracting all of these numbers by the term that comes prior to them, we will find that all of them result in 5. Because of this, we know that each time the term increases, 5 is being added to the numbers. Additionally, I noticed that all of the numbers in this arithmetic sequence only end in a 1 or a 6. Because of this, we can apply the same principle when adding 5 each time:

First term: 1
Second term: 6
Third term: 11
Fourth term: 16
Fifth term: 21
Sixth term: 26
Seventh term: 31
Eighth term: 36
Ninth term: 41
Tenth term: 46
Eleventh term: 51
Twelfth term: 56
Thirteenth term: 61
Fourteenth term: 66
Fifteenth term: 71

By adding 5 each time and keeping in mind that the digits all end in only 1 or 6, we will find that the fifteenth term results in 71. Therefore, the 15th term is 71.

Your final answer: The 15th term of this arithmetic sequence comes down to be 71. If you need extra help, let me know and I will gladly assist you.
4 0
2 years ago
1a. What is the product of 2x - 3 and 5x^2 - 2x + 6? Work and Answer:​
kiruha [24]

Answer:

I dont know.. sorry.......

8 0
2 years ago
Read 2 more answers
For each function, find f(-1), f(1), and f(3)<br> f(x)=3x-4
Anna [14]

Answer:

f(x)= 3x-4

f(-1)= 3*-1-4

f(-1)= 2-4

f(-1)= -2

f(x)= 3x-4

f(3)= 3*3-4

f(3)= 9-4

f(3)=5

f(x)= 3x-4

f(1)= 3*1-4

f(1)= 3-4

f(1)= -1

Step-by-step explanation:

6 0
2 years ago
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