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3 years ago

1.8+3.5y+0.9+9=16.2 plz help

Mathematics

1 answer:

saul85 [17]3 years ago

7 0

Answer:

The Awnser Is Y=9/7

Step-by-step explanation:

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What is the zero of the liner function of f(x)= 3x+18?

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Answer

The zero or roots would be x= -6

Step-by-step explanation:

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3 years ago

Erik is performing a marble experiment in math class. His teacher places an equal number of black, red, and white marbles in a b

olganol [36]

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1/3

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2 years ago

Find 3/8(3/4+5/6)−1/2. Write your answer as a fraction in simplest form.

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3 years ago

Use the confidence interval to find the estimated margin of error. Then find the sample mean. A biologist reports a confidence i

Pavlova-9 [17]

Answer:

$\bar X = \frac{Lower +Upper}{2}$

$\bar X= \frac{1.9+3.3}{2}= 2.6$

And the margin of error with this one:

$\bar X = \frac{Upper-Lower}{2}$

$ME = \frac{3.3-1.9}{2}= 0.7$

Step-by-step explanation:

Assuming that the parameter of interest is the sample mean $\mu$ . And we can estimate this parameter with a confidence interval given by this formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

For this case the confidence interval is given by (1.9, 3.3)

Since the confidence interval is symmetrical we can estimate the sample mean with this formula:

$\bar X = \frac{Lower +Upper}{2}$

$\bar X= \frac{1.9+3.3}{2}= 2.6$

And the margin of error with this one:

$\bar X = \frac{Upper-Lower}{2}$

$ME = \frac{3.3-1.9}{2}= 0.7$

7 0

3 years ago

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

zaharov [31]

After 6 years the investment is $5555.88

Step-by-step explanation:

A principal of $3600 is invested at 7.5% interest, compounded annually. How much will the investment be worth after 6 years?

The formula used to find future value is:

$A(t)=P(1+\frac{r}{n})^{nt}$

where A(t) = Accumulated amount

P = Principal Amount

r = annual rate

t= time

n= compounding periods per year

We are given:

P = $3600

r = 7.5 %

t = 6

n = 1

Putting values in formula:

$A(t)=P(1+\frac{r}{n})^{nt}\\A(t)=3600(1+\frac{0.075}{1})^{6*1}\\A(t)=3600(\frac{1.075}{1})^6\\A(t)=3600(1.075)^6\\A(t)=3600(1.543)\\A(t)=5555.88$

So, After 6 years the investment is $5555.88

Keywords: Compound Interest formula

Learn more about Compound Interest formula at:

#learnwithBrainly

8 0

3 years ago