What is the equation of a line that is perpendicular to the line y=- 1/4 x-1 and passes through the point (3, 7)?
1 answer:
Answer:
B. y = 4x - 5
Step-by-step explanation:
Line y = - 1/4 x - 1, has slope = - 1/4.
For perpendicular line slope should be negative reciprocal and = 4.
Slope point form is y - y1 = m(x - x1).
y - 7 = 4 (x - 3)
y - 7 = 4x - 12
y = 4x - 5
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