Answer:
HHH, W = 3-0 = 3
HHT, W= 2-1=1
HTH, W= 2-1=1
THH, W=2-1 =1
HTT, W= 1-2=-1
THT, W= 1-2=-1
TTH, W=1-2=-1
TTT, W=0-3 = -3
So then the sample space for W is:
![S= [-3,-1,1,3]](https://tex.z-dn.net/?f=%20S%3D%20%5B-3%2C-1%2C1%2C3%5D)
Just 4 possible values from 8 possible combinations for the 3 random tosses
Step-by-step explanation:
For this case we define W as the random variable who represent the number of heads minus the number of tails in three tosses of a coin.
W= # heads- # coins
Since we toss a coin 3 times we have 2*2*2= 8 possible results. We can list the results and the corresponding values for W like this:
HHH, W = 3-0 = 3
HHT, W= 2-1=1
HTH, W= 2-1=1
THH, W=2-1 =1
HTT, W= 1-2=-1
THT, W= 1-2=-1
TTH, W=1-2=-1
TTT, W=0-3 = -3
So then the sample space for W is:
![S= [-3,-1,1,3]](https://tex.z-dn.net/?f=%20S%3D%20%5B-3%2C-1%2C1%2C3%5D)
Just 4 possible values from 8 possible combinations for the 3 random tosses
Answer:
get wut?
Step-by-step explanation:
Answer:
The area lies to the right of the z-score 0.48 means all the values greater than it. This can be calculated on a graphing calculator using the function normCdf, where
- Lower bound = 0.48
- Upper bound = 9999
- Mean = 0
- Standard deviation = 1
<u>The result would be normCdf(0.48,9999,0,1) ≈ </u><u>0.315614</u>
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The area lies to the left of the z-score 0.79 means all the values less than it. This can be calculated on a graphing calculator using the function normCdf, where
- Lower bound = -9999
- Upper bound = 0.79
- Mean = 0
- Standard deviation = 1
<u>The result would be normCdf(-9999,0.79,0,1) ≈</u><u> 0.785236</u>
Answer:
x = 3
Step-by-step explanation:
49 - 19 = 30
-2x - 12x = 10x
30 / 10 = 3
There is 4 1/2 cups of green ooze