2 years ago

What is the equation of a line that is perpendicular to the line y=- 1/4 x-1 and passes through the point (3, 7)?

Mathematics

1 answer:

AleksandrR [38]2 years ago

4 0

Answer:

B. y = 4x - 5

Step-by-step explanation:

Line y = - 1/4 x - 1, has slope = - 1/4.

For perpendicular line slope should be negative reciprocal and = 4.

Slope point form is y - y1 = m(x - x1).

y - 7 = 4 (x - 3)

y - 7 = 4x - 12

y = 4x - 5

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