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2 years ago

What is the equation of a line that is perpendicular to the line y=- 1/4 x-1 and passes through the point (3, 7)?

Mathematics

1 answer:

AleksandrR [38]2 years ago

4 0

Answer:

B. y = 4x - 5

Step-by-step explanation:

Line y = - 1/4 x - 1, has slope = - 1/4.

For perpendicular line slope should be negative reciprocal and = 4.

Slope point form is y - y1 = m(x - x1).

y - 7 = 4 (x - 3)

y - 7 = 4x - 12

y = 4x - 5

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The temperature was -6°F. It rose so that the temperature was 0°F. What integers represents the change in temperature.

Flauer [41]

Answer:

Step-by-step explanation:

Just do $0 -(-6)$ .

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2 years ago

Monica is completing an Algebra test worth 100 points. There are 14 questions on the test that are equally valued. How many poin

Usimov [2.4K]

Answer:

7.1 points

Step-by-step explanation:

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2 years ago

Write and equati9n of a l8ne that passes through (1,-2) and is perpendicular to -4x+7y=21

yarga [219]

Given:

A line passes through (1,-2) and is perpendicular to $-4x+7y=21$ .

To find:

The equation of that line.

Solution:

We have, equation of perpendicular line.

$-4x+7y=21$

Slope of this line is

$m_1=-\dfrac{\text{Coefficient of x}}{\text{Coefficient of y}}$

$m_1=-\dfrac{-4}{7}$

$m_1=\dfrac{4}{7}$

Product of slope of two perpendicular lines is -1.

$m_1\times m_2=-1$

$\dfrac{4}{7}\times m_2=-1$

$m_2=-\dfrac{7}{4}$

Now, slope of required line is $-\dfrac{7}{4}$ and it passes through (1,-2). So, the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope.

$y-(-2)=-\dfrac{7}{4}(x-1)$

$4(y+2)=-7(x-1)$

$4y+8=-7x+7$

$4y+7x=7-8$

$7x+4y=-1$

Therefore, the equation of required line is $7x+4y=-1$ .

7 0

2 years ago

there are 6 twenty pound boxes and 8 sixty pound boxes of produce on a truck. how many pounds of produce are on the truck

Klio2033 [76]

6 *20 = 120

8 *60 = 480

120 + 480 = 600 pounds total

6 0

3 years ago

3x+112=5x+100 what is the answer I don't get it

slega [8]

Reorder the terms
112 + 3x = 100 + 5x
112 + 3x + (-5x) = 100 + 5x + (-5x)

Combine the like terms
5x + (-5x) = 0
112 + (-2x) = 100 + 0
112 + (-2x) = 100

112 + (-112) + (-2x) = 100 + (-112)
Combine like terms again
112 + (-112) =0
0 + (-2x) = 100 + (-112)
100 + (-112) = (-112) = (-12)
-2x = -12
-12 / -2 = 6
x = 6 <span>✓</span>

Check your work
3 * 6 + 112 = 130
5 * 6 + 110 = 130
130 = 130 ✓

3 0

2 years ago