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2 years ago

What is the equation of a line that is perpendicular to the line y=- 1/4 x-1 and passes through the point (3, 7)?

Mathematics

1 answer:

AleksandrR [38]2 years ago

4 0

Answer:

B. y = 4x - 5

Step-by-step explanation:

Line y = - 1/4 x - 1, has slope = - 1/4.

For perpendicular line slope should be negative reciprocal and = 4.

Slope point form is y - y1 = m(x - x1).

y - 7 = 4 (x - 3)

y - 7 = 4x - 12

y = 4x - 5

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2 years ago

3cis(5pi/4) in polar form

madreJ [45]

Rectangular form:
z = -2.1213203-2.1213203i

Angle notation (phasor):
z = 3 ∠ -135°

Polar form:
z = 3 × (cos (-135°) + i sin (-135°))

Exponential form:
z = 3 × ei (-0.75) = 3 × ei (-3π/4)

Polar coordinates:
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Cartesian coordinates:
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2 years ago

Is y=4x-1 proprtional

kozerog [31]

Do u mean Linear? if so it is

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3 years ago

How much must be added to each of the three numbers 1, 11, and 23 so that together they form a geometric progression?

Sliva [168]

Answer:

Step-by-step explanation:

Let x be unknown number which should be added to numbers 1, 11, 23 to get geometric progression. Then numbers 1 + x, 11 + x, 23 + x are first three terms of geometric progression.

Hence,

$b_1=1+x\\ \\b_2=11+x\\ \\b_3=23+x$

and

$b_2=b_1\cdot q\Rightarrow 11+x=(1+x)q\\ \\b_3=b_2\cdot q\Rightarrow 23+x=(11+x)q$

Express q:

$q=\dfrac{11+x}{1+x}=\dfrac{23+x}{11+x}$

Solve this equation. Cross multiply:

$(11+x)^2=(1+x)(23+x)\\ \\121+22x+x^2=23+x+23x+x^2\\ \\121+22x=23+24x\\ \\22x-24x=23-121\\ \\-2x=-98\\ \\2x=98\\ \\x=49$

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2 years ago