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VLD [36.1K]
3 years ago
8

One out of 3 students carpool to school. how many students out of 20 carpool

Mathematics
1 answer:
zhenek [66]3 years ago
5 0

Answer:

6

Step-by-step explanation:

20÷3=6 (give or take)

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What is 2x+3+8x=3x+9x+7
Reika [66]

Answer:

x=-2

Step-by-step explanation:

Hey there!

In order to solve this equation, you need to combine like terms

The equation after combining the x terms and the contants will look like this

10x+3=12x+7

Now you have to take 10x away from both sides

3=2x+7

Now bring all the constants to the left side

3-7=2x

Simplify

-4=2x

divide 2 on both sides to get x by itself

x=-2

So, the answer is x=-2

3 0
2 years ago
In the diagram below, f(x)=x^3+2x^2 is graphed. Also graphed is g(x), the result of a translation of f(x). Determine an equation
Art [367]

Answer:

g(x)=x^3+2x^2 - 4

Step-by-step explanation:

See attached worksheet

6 0
2 years ago
10 minutes to answer<br><br> Write an expression equivalent to<br><br> 4 - (-7) <br><br><br> help
Mama L [17]
11 because -7 subtracted by 4 add kore to the 7 so think of it this way -7 is a bad guy and 4 is a bad guy to because its a subtraction so if both bad guys combine you get 11 because a negative with negative makes a positive so its 11
4 0
2 years ago
ALEGBRA 1 ! help. me. please. this. is. so. hard. i dont. understand it.
ANEK [815]

Answer:

Part a) to find the maximum height of the snowball, you have to differentiate the function. Therefore you get ----> dh/dt= -32x-8 . Now equate this to zero and solve for x. x= (-1)/4 now sub this value in to find h(x) [note: i'm talking about the original function] . I got h max = h((-1)/4) = 9 which is the max height.

Step-by-step explanation:

I'm not too sure about the other questions. Sorry

8 0
3 years ago
Please help this question.
sergejj [24]

Answer:

a). 59.049°C

b). 2.1179 seconds

Step-by-step explanation:

Expression representing the final temperature after decrease in temperature of the metal from 100°C to T°C is,

T = 100(0.9)^{x}

where x = duration of cooling

a). Temperature when x = 5 seconds

T = 100(0.9)⁵

  = 59.049

  ≈ 59.049°C

b). If the temperature of the metal decreases from 100°C to 80°C

Which means for T = 80°C we have to calculate the duration of cooling 'x' seconds

80 = 100(0.9)^{x}

0.8 = (0.9)^{x}

By taking log on both the sides

log(0.8) =log[(0.9)^{x}]

-0.09691 = x[log(0.9)]

-0.09691 = -0.045757x

x = \frac{0.09691}{0.045757}

x = 2.1179

x ≈ 2.1179 seconds

3 0
3 years ago
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