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VashaNatasha [74]
3 years ago
8

What is the equation you use to determine the momentum of an object

Chemistry
1 answer:
klemol [59]3 years ago
5 0

The terms of a equation, the momentum of an object is equal to the mass of the object times the velocity of the object. where m is the mass and v is the velocity

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Which of the following pairs of elements would most likely combine to form a salt?
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I think it’s Ca and Cs
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Track runner will all cover the same distance. The winner will take
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This question sadly does not make much sense, please rephrase it.

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How do wildfires impact animal behavior?
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An ionic compound is composed of the following elements:
Amiraneli [1.4K]

Answer: N3 H12 P O3

Explanation:

From the question :

N = 31.57% H = 9.10% P = 23.27%

O= 36.06%

Divide each of the element by their respective relative atomic masses.

N = 31.57 / 14 = 2.26

H = 9.10/ 1 = 9.10

P = 23.27 / 31= 0.750

O =36.06 / 16 = 2.25

Divide each answer by the lowest of them all, we then have:

N = 2.26/ 0.750 = Approx = 3

H = 9.10 / 0.750 = Approx = 12

P = 0.750/ 0.750= 1

O = 2.25 / 0.750 = Approx = 3

The empiral formula is

N3 H12 P O3

6 0
3 years ago
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Write the balanced standard combustion reaction for the c5h7on3s2
AlexFokin [52]

Answer:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Explanation:

When C5H7ON3S2 under go Combustion, the following are obtained as illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

Now, let us balance the equation. This is illustrated below:

C5H7ON3S2 + O2 —> CO2 + H2O + N2 + S2

There are 3 atoms of N on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of C5H7ON3S2 and 6 in front of N2 as shown below:

4C5H7ON3S2 + O2 —> CO2 + H2O + 6N2 + S2

There are 20 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 20 in front of CO2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + H2O + 6N2 + S2

There are 28 atoms on H on the left side and 2 atoms on the right side. It can be balance by putting 14 in front of H2O as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + S2

There are 8 atoms of S on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of S2 as shown below:

4C5H7ON3S2 + O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, there are a total of 54 atoms of O on the right side and 6 atoms on the left side

It can be balance by putting 25 in front of O2 as shown below:

4C5H7ON3S2 + 25O2 —> 20CO2 + 14H2O + 6N2 + 4S2

Now, we can see that the equation is balanced.

4 0
2 years ago
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