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VashaNatasha [74]
3 years ago
8

What is the equation you use to determine the momentum of an object

Chemistry
1 answer:
klemol [59]3 years ago
5 0

The terms of a equation, the momentum of an object is equal to the mass of the object times the velocity of the object. where m is the mass and v is the velocity

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Which statement describes a controlled experiment? A.) It has one group in which the controlled variable is tested, and another
scoundrel [369]

Answer:C.) It has one group in which the manipulated variable is tested, and another in which the responding variable is tested

Explanation: hope this helps

6 0
3 years ago
The electron configuration of an element is shown below.
gayaneshka [121]

Answer:it is in group 7

Explanation:it is in this group because in the increasing number of atomic number the element is found in group seven. The element is likely to receive 3 electrons while bonding with another element to make it stable.

5 0
2 years ago
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Balance the following redox reaction if it occurs in acidic solution. What are the coefficients in front of h2c2o4 and h2o in th
postnew [5]

The balanced redox reaction, if it occurs in acidic solution, is

5C₂O₄²⁻(aq) + 2MnO₄⁻(aq) + 16H⁺-----> 10CO₂(g) + 2Mn²⁺(aq) + 8H₂O(l)

<h3>What are redox reaction?</h3>

Redox reactions are those in which loss and again of electrons occur.

To balance the redox reaction, we must first break the whole reaction into half equations;

Oxidation half equation

\rm 5C_2O4^2^-(aq) + 10e + 8H^+----- > 10CO_2(g) + 4H_2O(l)

Reduction half equation

\rm 2MnO_4^- (aq) + 10e + 8H^+----- > 2Mn^2+(aq) + 4H_2O(l)

Now combine both the reactions

\rm 5C_2O_4^2-(aq) + 2MnO4^- (aq) + 16H^+----- > 10CO_2(g) + 2Mn^2+(aq) + 8H_2O(l)

Thus, the coefficient of H₂C₂O₄ is 5 and that of water is 8.

Learn more about redox reactions

brainly.com/question/13293425

#SPJ4

8 0
1 year ago
If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?
photoshop1234 [79]
The combustion reaction is as expressed,

                CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
       mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g. 

     moles of C = 0.86 g C / 12 g = 0.0713
     moles of H = 0.14 g H / 1 g  = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.
7 0
3 years ago
What type of fault usually occurs because of compression?
lianna [129]

Answer:c

Explanation:

4 0
3 years ago
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