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Alex_Xolod [135]
3 years ago
15

In the following reaction, what is the effect of adding more NO2 to the starting reaction mixture?

Chemistry
1 answer:
Mars2501 [29]3 years ago
5 0

Answer:

It would increase the final quantity of products

Explanation:

According to the Le- Chatelier principle,

At equilibrium state when stress is applied to the system, the system will behave in such a way to nullify the stress.

The equilibrium can be disturb,

By changing the concentration

By changing the volume

By changing the pressure

By changing the temperature

Consider the following chemical reaction.

Chemical reaction:

2NO₂ ⇄ N₂O₄

In this reaction the equilibrium is disturb by increasing the concentration of reactant.

When the concentration of reactant is increased the system will proceed in forward direction in order to regain the equilibrium. Because when reactant concentration is high it means reaction is not on equilibrium state. As the concentration of NO₂ increased the reaction proceed in forward direction to regain the equilibrium state and more product is formed.

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What do helium (He), neon (Ne), and argon (Ar) have in common?
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The ammonia molecule in the diagram has the observed bond orientation because ...
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Answer:

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Explanation:

The shape and the bond orientation of molecules and ions are both explained by the valences shell electron pair repulsion theory (VSEPR).

Ammonia, NH_3, is a molecule which contains three N-H bonds, as well as one lone pair on nitrogen. According to the VSEPR theory, molecules try to acquire a shape which would minimize the repulsion exhibited by the electron clouds present, that is, between the bonding (shared in a bond) and non-bonding (lone pair) electrons.

In VSEPR, our main step is to calculate the steric number, this is the sum of the number of bonds (ignoring the multiplicity of any bond) and the lone pairs on a central atom. In ammonia, we have 3 bonds and 1 lone pair, totaling to a steric number of 4. A steric number of 4 without any lone pairs on a central atom and just bonds would yield a tetrahedral shape with bond angles of 109.5^o.

Now, in this case, since we have a lone pair instead of a bond, it is repelling stronger decreasing the bond angles to about 107^o.

The greater the number of lone pairs, the lower the angle becomes.

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