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Sergeeva-Olga [200]
4 years ago
11

What is oxidation number for Mn in Mn2O7 ( sign and number)

Chemistry
2 answers:
Anna11 [10]4 years ago
6 0

Answer : The oxidation number of sulfur (Mn) is, (+7)

Explanation :

Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.

It is generally written with the sign (+) and (-) first and then the magnitude.

When the atoms are present in their elemental state then the oxidation number will be zero.

The oxidation number of  oxygen (O)  in compounds is usually -2.

The given compound is, Mn_2O_7

Let the oxidation state of Mn be, 'x'

2x+7(-2)=0\\\\2x-14=0\\\\x=\frac{+14}{2}\\\\x=+7

Therefore, the oxidation number of sulfur (Mn) is, (+7)

yKpoI14uk [10]4 years ago
5 0

The oxidation number for Mn in Mn2O7 is +7. The oxidation number of manganese (Mn) in potassium permanganate (KMnO4) is +5. 

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A compound was found to be soluble in water. It was also found that addition of acid to an aqueous solution of this compound res
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c. Cr

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The compound is containing CO_3^2- ion.

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Which phrase best describes a period on the periodic table?
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<u>d. a row of elements</u>

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Why the enthalpy of Ba(oh)2 +h2so4 is greater than Ba(oh)2 + hcl?​
Rina8888 [55]

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Which of the following transition is considered the phase<br> change from water to steam?
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You have come down with a nasty cold and would like to understand why the virus that infected you is making you feel so lousy. W
umka21 [38]

Answer:

a) The volume is 5.236x10⁻¹³L

b) The molarity of a single virus is 1.91x10¹² mol/L

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Explanation:

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M=\frac{number-of-moles}{volume-of-solution}

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M=\frac{1}{5.236x10^{-13} } =1.91x10^{12} mol/L

c) For a 100 virus particles the molarity is:

M=\frac{100}{5.236x10^{-13} } =1.91x10^{14} mol/L

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