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alex41 [277]
3 years ago
7

Really would appreciate some help thank u x

Mathematics
1 answer:
vivado [14]3 years ago
7 0

Answer:

\sqrt[12]{48}

es igual a 1,380 (decimal)

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A forest ranger can see a distance of 12 miles from a fire tower how many square miles can he see
ioda
He see a circle, so you need to find the area.
A = π * r²
A = π * 12²
A =  3.14 * 144 =

A = 452.16 miles²
6 0
3 years ago
Two numbers have the ratio of 4:7 if their sum is 143 what are the numbers?
garri49 [273]

Answer:

52:91

Step-by-step explanation:

To find a ratio value you need to think of it more as two numerators that together equal one whole. 4+7 is 11 so that would be the denominator. If the sum is 143, then we divide by 11 since one number is 4/11s of 143, and the other is 7/11s of 143. 143/11=13

now we multiply both:

4(13)=52

7(13)=91

Check:

91+52=143

52/91 simplifies to 4/7 or 4:7

i hope this helps!

3 0
3 years ago
Y = 3x – 21 is it proportional
pochemuha

Answer:

yes  

Step-by-step explanation:

4 0
3 years ago
What is 4/10 plus 5/100?
storchak [24]

Answer:

0.45

Step-by-step explanation:

4/10 is 0.4

and

5/100 is 0.05

5 0
3 years ago
Derivatives concept:<br> Exercises using the definition of derivatives:<br><br> (Full development)
krok68 [10]

(A) <em>f(x)</em> = 7 is constant, so <em>f(x</em> + <em>h)</em> = 7, too, which makes <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 0. So <em>f'(x)</em> = 0.

(B) <em>f(x)</em> = 5<em>x</em> + 1   ==>   <em>f(x</em> + <em>h)</em> = 5 (<em>x</em> + <em>h</em>) + 1 = 5<em>x</em> + 5<em>h</em> + 1

==>   <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 5<em>h</em>

Then

\displaystyle f'(x) = \lim_{h\to0}\frac{5h}h = \lim_{h\to0}5 = 5

(C) <em>f(x)</em> = <em>x</em> ² + 3   ==>   <em>f(x</em> + <em>h)</em> = (<em>x</em> + <em>h</em>)² + 3 = <em>x</em> ² + 2<em>xh</em> + <em>h</em> ² + 3

==>   <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 2<em>xh</em> + <em>h</em> ²

\implies\displaystyle f'(x) = \lim_{h\to0}\frac{2xh+h^2}h = \lim_{h\to0}(2x+h) = 2x

(D) <em>f(x)</em> = <em>x</em> ² +<em> </em>4<em>x</em> - 1   ==>   <em>f(x</em> + <em>h)</em> = (<em>x</em> + <em>h</em>)² + 4 (<em>x</em> + <em>h</em>) - 1 = <em>x</em> ² + 2<em>xh</em> + <em>h</em> ² + 4<em>x</em> + 4<em>h</em> - 1

==>   <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 2<em>xh</em> + <em>h</em> ² + 4<em>h</em>

\implies \displaystyle f'(x) = \lim_{h\to0}\frac{2xh+h^2+4h}h = \lim_{h\to0}(2x+h+4) = 2x+4

5 0
3 years ago
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