This is a arithmetic sequence, so all we need to do is subtract the numbers and find the common difference.
40 - 24 = 16
56 - 40 = 16
72 - 56 = 16
Therefore, the common difference is 16.
Best of Luck!
Where the 2 lines meet in the middle to form an X
<span>Thus, a product that normally costs $199 with a 5 percent discount will cost you $189.05, and you saved $9.95.</span>
<span>You can also calculate how much you save by simply moving the period in 05.00 percent two spaces to the left, and then multiply the result by $199 as follows: $199 x .05 = $9.95 savings.</span>
<span>Furthermore, you can get the final price by simply deducting .05 from 1 and multiplying it by $199 as follows: (1 - .05) x $199 = $189.05 final price. </span>
<span>If something costs $199 and is on sale for 5% off, then how much would it cost? Here we will show you how to calculate how much you save (discount) and how much you have to pay if something you want to buy is regularly $199, but is currently on sale for 5 percent off.
<span>$199
<span>SALE
</span>5% OFF</span>
There are many ways of calculating your discount and final purchase price. One way is to multiply 199 dollars by 5 percent, and then divide the answer by one hundred, then deduct that result from the original price. See illustration below:
+ Purchase Price = $199
- Discount (199 x 5)/100 = $9.95
<span>= Final Price 199 - 9.95 = $189.05
</span></span><span><span>Hope this helps you! <3</span></span>
Answer:
The company should promote a lifetime of 3589 hours so only 2% burnout before the claimed lifetime
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
What lifetime should the company promote for these bulbs, whereby only 2% burnout before the claimed lifetime?
This is the value of X when Z has a pvalue of 0.02. So it is X when Z = -2.055.
The company should promote a lifetime of 3589 hours so only 2% burnout before the claimed lifetime
