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Butoxors [25]
3 years ago
12

ASAP PLEASE HELP ME

Mathematics
2 answers:
pogonyaev3 years ago
6 0

Answer:

108

Step-by-step explanation:

All you need to do in area is just multiply them together. If  that was what you were looking for.    Or 6x8=48

10x4=40

5x4=20

48+40+20=108 for a different way.

xxTIMURxx [149]3 years ago
3 0

Answer:

108

Step-by-step explanation:

6x8=48

10x4=40

5x4=20

48+40+20=108

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Pls help with this someone i'm struggling with this!
AfilCa [17]

Answer:

x=9

Step-by-step explanation:

Remove the radical by raising each side to the index of the radical.

5 0
3 years ago
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Given that f(a+b)= f(a) + f(b) and f(x) is always positive, what os the value of f(0)?
FrozenT [24]
This is a strange question, and f(x) may not even exist. Why do I say that? Well..

[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).

[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!

Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.

To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
4 0
3 years ago
HELLPP this is due in 7 minutes
olchik [2.2K]

Answer:

a

Step-by-step explanation:

8 0
3 years ago
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Invasive species often experience exponential population growth when introduced into a new environment. Zebra mussels are an inv
Oliga [24]

Answer:

If ‘a’ is the initial population of the Zebra mussels, then every six months, the population of Zebra mussels quadruples, i.e. it becomes 4a. In t years, i.e. in 2t intervals of 6 months each, the population of Zebra mussels can be computed with the help of a geometric series a, ar, ar2, ar3, …. arn-1 ( the series being finite with n terms) where a is the 1st term , r is the common ratio and n is the number of terms in the series..

Here, in 2t years, there will be 2t + 1 terms in the geometric series including the initial term. Thus in the above series, a = 10, r = 4 and n = 2t + 1. Then the population of the Zebra mussels after 2t years is the (2t +1)st term of the geometric series I.e. 10* ( 42t)                  

In 15 months, t = 15/12 = 1.25. Then the population of Zebra mussels after 15 months will be 10*(42.5 ) = 10 * 25 = 320

If after t years, the population of the Zebra mussels become 1 million , then we have

1000000 = 10 * (42t) or, 100000= 42t or,105 = 42t    Taking logarithms of both sides, we have 5 log 10 = 2t log 4 or, t = (5log10)/(2log4) = 5/1.20 years or (5/1.20) * 12 months = 50 months, i.e. 4 years and 2 months.

Step-by-step explanation:

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