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Butoxors [25]
3 years ago
12

ASAP PLEASE HELP ME

Mathematics
2 answers:
pogonyaev3 years ago
6 0

Answer:

108

Step-by-step explanation:

All you need to do in area is just multiply them together. If  that was what you were looking for.    Or 6x8=48

10x4=40

5x4=20

48+40+20=108 for a different way.

xxTIMURxx [149]3 years ago
3 0

Answer:

108

Step-by-step explanation:

6x8=48

10x4=40

5x4=20

48+40+20=108

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The amusement park won't allow kids to ride
n200080 [17]
I think the answer is C
6 0
3 years ago
50 POINTS!!!!!!!
nevsk [136]

Answer: Option C)1 over 15 minus 1 over x equals 1 over 20

Explanation:

Since, Micah can fill a box with books in 15 minutes.

Therefore, the work done by Micah in one minute= 1/15

Also, Sydney takes the books out puts them on a shelf.

And the times taken by Micah when Sydney is also taking the books outside from the self= 20 minutes

Therefore, the work done by Micah in one minute when Sydney  taking books out of the box= 1/20

Let Sydney alone takes x minutes to take books outsides the shelf.

Then, work done by Sydney in one minute=1/x

Thus, the work done by Sydney( by taking books out of the box)=  the work done by Micah - work done by Micah and Sydney simultaneously= 1/15-1/20

⇒1/x=1/15-1/20

⇒1/15-1/20=1/x

⇒1/15-1/x=1/20 is the required expression.

Therefore, Option C is correct.



4 0
3 years ago
Read 2 more answers
If sin(x) = 5/13, and x is in quadrant 1, then tan(x/2) equals what?
Rufina [12.5K]
x is in quadrant I, so 0, which means 0, so \dfrac x2 belongs to the same quadrant.

Now,

\tan^2\dfrac x2=\dfrac{\sin^2\frac x2}{\cos^2\frac x2}=\dfrac{\frac{1-\cos x}2}{\frac{1+\cos x}2}=\dfrac{1-\cos x}{1+\cos x}

Since \sin x=\dfrac5{13}, it follows that

\cos^2x=1-\sin^2x\implies \cos x=\pm\sqrt{1-\left(\dfrac5{13}\right)^2}=\pm\dfrac{12}{13}

Since x belongs to the first quadrant, you take the positive root (\cos x>0 for x in quadrant I). Then

\tan\dfrac x2=\pm\sqrt{\dfrac{1-\frac{12}{13}}{1+\frac{12}{13}}}

\tan x is also positive for x in quadrant I, so you take the positive root again. You're left with

\tan\dfrac x2=\dfrac15
4 0
3 years ago
If u help me then i will love you forever
Darina [25.2K]

ok what do u need help with I don't see anything

7 0
3 years ago
What is 0.5 repeating in fraction form?
aev [14]
.555555555555555555 =5/9
5 0
3 years ago
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