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Illusion [34]
3 years ago
7

Andy Benton works at the local Starbucks coffee shop and his responsibilities include taking orders, fulfilling orders, and ring

ing in sales. At what level of the organizational pyramid would you categorize Andy?
A. Strategic
B. Owner
C.Operational
D. Managerial
Physics
1 answer:
mr_godi [17]3 years ago
5 0

Answer:

option C.

Explanation:

The correct answer is option C.

The owner is at the top of the organizational pyramid he owns the organization and all the investment is done by the owner.

Strategic teams do all the strategy related work like how to increase production, decrease the losses, how to increase the quality, etc.

Operational team deals with the work which is related to taking work, assigning work and giving the result to the higher authority.

hence, the work of Andy Benton matches with the duties of the Operation team

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HELP!!!!!!!!!
Irina18 [472]

Answer:

4.096 kW

Explanation:

Applying,

P = Fvcos∅................. Equation 1

Where P = Power of the motor, F = Force exerted on the motor, v = Velocity, ∅ = angle.

From the question,

Given: F = 500 N, v = 10 m/s, ∅ = 35°

Substitute these values into equation 1

P = 500×10×cos35°

P = 4095.8 W

P = 4.096 kW

Hence the power rating of the moto in kW is 4.096 kW

8 0
3 years ago
a 65kg bicyclists rides his 8.8kg bicycle with a speed of 14m/s...(a) how much work must be done by the brakes to bring the bike
Sergeu [11.5K]

(a) The total mass of the bicycle+rider system is

m=65 kg+8.8 kg=73.8 kg

And their initial kinetic energy is

K= \frac{1}{2}mv^2= \frac{1}{2}(73.8 kg)(14 m/s)^2=7232 J

For the work-energy theorem, the work done by the brakes to stop the bicycle+rider must be equal to the loss of kinetic energy of the system:

W=K_f -K_i

And so, since the final kinetic energy Kf is zero (because the  final velocity is zero), then we have

W=-K_i = -7232 J

Where the negative sign is due to the fact that the work done by the brakes is against the motion of the bicycle.

(b) First we can calculate the acceleration of the bicyle; since the final speed is zero, we have

a= \frac{v_f-v_i}{t} = \frac{-14 m/s}{4 s}=-3.5 m/s^2

where the negative sign means it is a deceleration.

Then we can find the distance covered by using the relationship:

2aS = v_f^2 - v_i^2

So we have

S= \frac{-v_i^2}{2a}= \frac{-(14 m/s)^2}{2 (-3.5 m/s^2)}=28 m

So, the bike and the rider traveled for 28 meters before to stop.

(c) The work done by the brake force is:

W=Fd

where F is the brake force and d is the distance covered by the bike+rider during the time of application of the force, so it is d=S=28 m.

Therefore, the brake force is (we can neglect signs because we are only interested in the magnitude of the force):

F= \frac{W}{d}= \frac{7232 J}{28 m}=258.3 N

4 0
3 years ago
Read 2 more answers
14. After finishing her homework, Sue climbs up a 5.00 m high flight of stairs to her bedroom
OleMash [197]

Explanation:

Given parameters:

Height  = 5m

Mass of Sue  = 50kg

Unknown:

Magnitude of Sue's weight  = ?

Work done by Sue = ?

Solution:

Weight is the vertical force exerted by a body in the presence of gravity.

Mathematically;

        W = mg

m is the mass

g is the acceleration due to gravity  = 9.8m/s²

  Weight  = 50 x 9.8  = 490N

Work done  = Force x distance = weight x height

 Work done  = 490 x 5 = 2450J

3 0
3 years ago
How is sound different from wind?​
Mashutka [201]

Answer:

Wind - the perceptible natural movement of the air, especially in the form of a current of air blowing from a particular direction. Sound wave - a wave of compression and rarefaction, by which sound is propagated in an elastic medium such as air.

Sound wave travels faster in the air when it is with the wind. ... In contrast, when sound wave travels against the wind, that is, when it travels in the opposite direction with the wind, the speed of sound will be reduced by the wind speed, resulting in a lower speed in the upper region.

Explanation:

please mark me brainliest

3 0
3 years ago
Object 1 has a mass of 7.0kg and a initial velocity of 17.0 m/s. Object 2 has a mass of 8.0kg and a initial velocity of -14.0 m/
Naily [24]

\\ \sf\longmapsto m1v1+m2v2=(m1+m2)v3

\\ \sf\longmapsto 7(17)+8(-14)=(7+8)v3

\\ \sf\longmapsto 119-112=15v3

\\ \sf\longmapsto 15v3=7

\\ \sf\longmapsto v3=7/15

\\ \sf\longmapsto v3=2.1m/s

4 0
3 years ago
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