The gravitational force between the two balls is 
Explanation:
The magnitude of the gravitational force between two objects is given by:
where
:
is the gravitational constant
m1, m2 are the masses of the two objects
r is the separation between the objects
For the balls in this problem, we have
r = 0.74 m
Substituting into the equation, we find the gravitational force between the two balls:
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Answer:
well for one it can be from drilling or when water starts to breck down the rocks
Explanation:
Answer:
Explanation:
Given an RL circuit
A voltage source of.
V = 108V
A resistor of resistance
R = 1.1-kΩ = 1100 Ω
And inductor of inductance
L = 34 H
After he inductance has been fully charged, the switch is open and it connected to the resistor in their own circuit, so as to discharge the inductor
A. Time the inductor current will reduce to 12% of it's initial current
Let the initial charge current be Io
Then, final current is
I = 12% of Io
I = 0.12Io
I / Io = 0.12
The current in an inductor RL circuit is given as
I = Io ( 1—exp(-t/τ)
Where τ is time constant and it is given as
τ = L/R = 34/1100 = 0.03091A
So,
I = Io ( 1—exp(-t/τ))
I / Io = ( 1—exp(-t/τ))
Where I/Io = 0.12
0.12 = 1—exp(-t/τ)
0.12 — 1 = —exp(-t/τ)
-0.88 = -exp(-t/0.03091)
0.88 = exp(-t/0.03091)
Take In of both sides
In(0.88) = In(exp(-t/0.03091)
-0.12783 = -t/0.030901
t = -0.12783 × 0.030901
t = 3.95 × 10^-3 seconds
t = 3.95 ms
B. Energy stored in inductor is given as
U = ½Li²
So, the current at this time t = 3.95ms
I = Io ( 1—exp(-t/τ))
Where Io = V/R
Io = 108/1100 = 0.0982 A
Now,
I = Io ( 1—exp(-t/τ))
I = 0.0982(1 — exp(-3.95 × 10^-3 / 0.030901))
I = 0.0982(1—exp(-0.12783)
I = 0.0982 × 0.12
I = 0.01178
I = 11.78mA
Therefore,
U = ½Li²
U = ½ × 34 × 0.01178²
U = 2.36 × 10^-3 J
U = 2.36 mJ
Answer:
The answer to the question is
The ball will go 0.14 meters high if the gun is aimed vertically
Explanation:
The energy in the spring → Energy, E = 
Where E = energy in the spring
k = Spring constant
x = Spring compression or stretch
Therefore E = 
The spring energy is transferred to the ball as kinetic energy based on the first law of thermodynamics which states that energy is neither created nor destroyed
Kinetic energy = KE = 
From which v = 
= 
= 1.66 m/s
from v² =u² - 2·a·S
Where v = final velocity = 0 m/s
u = initial velocity = 1.66 m/s
a = g = Acceleration due to gravity
S = height
Therefore 0 = 1.66² - 2×9.81×S
or S = 1.66² ÷ (2×9.81) = 0.14 m
