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aivan3 [116]
3 years ago
15

A client experiences difficulty in performing the prone iso-abs exercise. Which of the following should be suggested as an regre

ssion?
a. Quadruped arm and opposite leg raiseb. Cable rotationc. Rolling active resistance rowd. Cable chop
Physics
1 answer:
attashe74 [19]3 years ago
6 0

Answer:

a. Quadruped arm and opposite leg raise

Explanation:

A client experiences difficulty in performing the prone iso-abs exercise, because the regression is Quadruped arm and opposite leg raise.

Iso-abs exercise is a beginner exercise that stabilizes the core muscle. Press the hips together. Slowly lift the pelvis from the floor til the back is straight. Carry  this position for the desired time or til proper form bcomes difficult to maintained.

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A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear
Talja [164]

Answer:

70.07 Hz

Explanation:

Since the sound is moving away from the observer then

f_o = f_s\frac {(v+vs)}{v} and f_o = f_s\frac {(v-vs)}{v} when moving towards observer

With f_o of 76 then taking speed in air as 343 m/s we have

76 = f_s\times\frac {(343-vs)}{343}

f_s=\frac {343\times 76}{343-v_s}

Similarly, with f_o of 65 we have

65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}

Now

f_s=\frac {343\times 65}{343+v_s}=\frac {343\times 76}{343-v_s}

v_s=27.76 m/s

Substituting the above into  any of the first two equations then we obtain

f_s=70.07 Hz

4 0
3 years ago
A small steel wire of diameter 1.0mm is connected to an oscillator and is under a tension of 5.7N . The frequency of the oscilla
kotegsom [21]

Answer:

The power output of the oscillator is 0.350 watt.

Explanation:

Given that,

Diameter = 1.0 mm

Tension = 5.7 N

Frequency = 57.0 Hz

Amplitude = 0.54 cm

We need to calculate the power output of the oscillator

Using formula of the power

P=\dfrac{1}{2}\times\mu\times\omega^2\times a^2\times v

Put the value into the formula

P=\dfrac{1}{2}\times A\times\rho\times\omega^2\times a^2\times\dfrac{\sqrt{T}}{\mu}

P=\dfrac{1}{2}\times3.14\times(0.0005)^2\times7850\times(2\times\pi\times57.0)^2\times(0.54\times10^{-2})^2\times\sqrt{\dfrac{5.7}{3.14\times(0.0005)^2\times7850}}

P=0.350\ Watt

Hence, The power output of the oscillator is 0.350 watt.

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3 years ago
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69 i agree with her hope this helps
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Answer:

friction

Explanation:

the road is the pathway for the vehicle so the tures create friction to stay sturdie

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