Answer:
2/15
Step-by-step explanation:
first you have to make both numbers have an equal denominator the subtract how much that was left from how much she Initially ate
Answer:
The answer is 3 , 1 , 2 .
Step-by-step explanation:
I will give an example.
e.g.
x² + 3x + 2
Step 3 :
Set the equation equal to zero :
x² + 3x + 2 = 0
Step 1 :
Completely factor the equation :
x² + x + 2x + 2 = 0
x(x+1) + 2(x+1) = 0
(x+2)(x+1) = 0
Step 2 :
Set each factor equal zero and then solve for the variable :
(x+2)(x+1) = 0
x + 2 = 0
x = -2
x + 1 = 0
x = -1
Answer:
A task time of 177.125s qualify individuals for such training.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem, we have that:
A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so
.
The fastest 10% are to be given advanced training. What task times qualify individuals for such training?
This is the value of X when Z has a pvalue of 0.90.
Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when
.
So




A task time of 177.125s qualify individuals for such training.
Answer:
(5 , 7)
Step-by-step explanation:
let a = the number of adult tickets
let c = the number of children tickets
then we have to solve the following system
a + c = 12
14.5a + 9c = 135.5
we proceed by Substitution:
c = 12 - a
14.5a + 9c = 135.5
After some calculations we find
a=5 and c=7