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2 years ago

20 POINTS 20POINTS.........................

Mathematics

1 answer:

wlad13 [49]2 years ago

6 0

Answer:

thank you god bless you

Step-by-step explanation:

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Answer:

26.8<u>3</u>

Step-by-step explanation:

5/6=0.83333 repeating

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Given the function f(x)= x^4 - 4x^3 -2, determine the absolute minimum value of ff on the closed interval [-2, 4].

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2 years ago

Use the quadratic formula to find the solutions to the equation x^2-3x+1=0

Gnom [1K]

Answer:

$x_{1}=\frac{+3+\sqrt{5} }{2}\\\\x_{2}=\frac{+3-\sqrt{5} }{2}$

Step-by-step explanation:

Using:

$x=\frac{-b+-\sqrt{b^{2}-4*a*c} }{2*a}$

we will have two solutions.

x^2-3x+1=0

So, a=1 b=-3 c=1

$x_{1}=\frac{+3+\sqrt{-3^{2}-4*1*1} }{2*1}\\\\x_{2}=\frac{+3-\sqrt{-3^{2}-4*1*1} }{2*1}$

We have two solutions:

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2 years ago

What is the width of a rectangle with length 5.5 cm and area 220 cm???

Aleks04 [339]

40 cm. Just divide the area by the length. Hope this helps!

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