2.50-2.00=0.5
2.50/0.5= 5 = 100%
2.00/0.5=4 = 80%
100-80= 20%
3(y-1)=y-11
Distribute:
3y - 1 = y- 11
Add 11 to both sides
3y - 12 = y
subtract 3y on both sides
-12 = -2y
Divide by 2y
y= 6
Answer:
$ 2,600 was invested at 4% and $ 3,600 was invested at 9%.
Step-by-step explanation:
Given that in investing $ 6,200 of a couple's money, a financial planner put some of it into a savings account paying 4% annual simple interest, and the rest was invested in a riskier mini-mall development plan paying 9% annual simple interest, and the combined interest earned for the first year was $ 428, to determine how much money was invested at each rate, the following calculation must be performed:
3000 x 0.04 + 3200 x 0.09 = 408
2500 x 0.04 + 3700 x 0.09 = 433
2600 x 0.04 + 3600 x 0.09 = 428
Therefore, $ 2,600 was invested at 4% and $ 3,600 was invested at 9%.
Z scores are (age - mean) / std dev
= 23 - 27 / 2 = -2 and 27-27 / 2 = 0
Using the standard normal tables we find the required percentage is 47.73%
