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3 years ago

Place decimal points in 34, 4, and 417 so that the sum of the three numbers is 7.97.

Mathematics

1 answer:

KIM [24]3 years ago

8 0

3.4+0.4+4.17=7.97 you just have to try different combinations of different numbers with the decimals.

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White raven [17]

Answer:

4 PS ≅ RQ

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3 years ago

√x+4=√3x <br><br> A.) x=2<br> B.) x=-2<br> C.) x=3<br> D.) x=-3

Agata [3.3K]

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3 years ago

Read 2 more answers

A police department reports that the number of reported rapes in their jurisdiction increased by 100% over the past decade. This

Dmitrij [34]

Answer:

the rate growed so they are more rapes now than the past decade

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2 years ago

Colby is making a home video consisting of a 5-minute introduction followed by several short skits. Each skit is 6 minutes long.

givi [52]

<h2>Hello!</h2>

The answer is: There are a total of 16 skits in the video.

From the statement, we know that the total length of the video is 101 minutes and it contains a 5-minute introduction, the rest of the minutes are short skits (which are 6 minutes long each one).

So, we need to write the following equations:

First equation:

$TotalDuration=Introduction+n*Skit$

Second equation:

$Skit=6Minutes$

Where,

$TotalDuration=101Minutes\\Introduction=5Minutes\\n=NumberOfSkits\\Skit=6Minutes$

So, replacing and substituting the second equation into the first equation we have:

$101Minutes=5Minutes+n*6Minutes\\n*6Minutes=101Minutes-5Minutes\\n*6Minutes=96Minutes\\n=\frac{96Minutes}{6Minutes}=16$

So, there are a total of 16 skits in the video.

Let's prove it substituting "n" into the first equation:

$101Minutes=5Minutes+16*6minutes\\101Minutes=5Minutes+96Minutes\\101Minutes=101Minutes$

Have a nice day!

8 0

3 years ago

A recent survey indicated that the average amount spent for breakfast by business managers was $9.33 with a standard deviation o

olasank [31]

Answer:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3$

Step-by-step explanation:

Information given

$\bar X=9.41$ represent the sample mean

$s=0.24$ represent the sample standard deviation

$n=81$ sample size

$\mu_o =9.33$ represent the value to verify

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true mean is higher than 9.33, the system of hypothesis would be:

Null hypothesis: $\mu \leq 9.33$

Alternative hypothesis: $\mu > 9.33$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3$

4 0

3 years ago