What is the answer to x^2= -2

Mathematics

1 answer:

igomit [66]3 years ago

6 0

√-2 Ndndndndnbdbdbfbffnfnf

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All the answers please on paper and work

REY [17]

1)
8² + 15² = 17²
64 + 225 = 289
This is true, so the triangle is a right triangle.

2)
4² + 12² = 13²
16 + 144 = 169
This is false, so the triangle is not a right triangle.

3)
20² + 21² = 27²
400 + 441 = 729
This is false, so the triangle is not a right triangle.

4)
28² + 45² = 53²
784 + 2,025 = 2,809
This is true, so the triangle is a right triangle.

7 0

3 years ago

2. Sketch the graph with the points (-1,1) and (1,5) on a coordinate plane. Then, identify the y-

Akimi4 [234]

Answer:

y-intercept: (0, 3)

Step-by-step explanation:

Attached is a screenshot of the plotted points (-1, 1) and (1, 5) on a graph. It shows that the line crosses the y-axis at point (0, 3) → which is the y-intercept.

Please mark my answer as the Brainliest, if you find this helpful :)

4 0

2 years ago

A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

$^nC_r=\dfrac{n!}{(n-r)!r!}$

Given : Total multiple-choice questions = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= $^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84$

No. of ways to answer 4 open-ended problems

= $^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15$

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= $84\times15=1260$