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Ksju [112]
3 years ago
5

Given A is between Y and Z, and YA=14x, AZ=10x and YZ=12x+48, solve for x​

Mathematics
1 answer:
iren [92.7K]3 years ago
6 0

Answer:The answers are: 4 40 56 96.

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Use a matrix equation to solve the system of linear equations. left brace Start 2 By 1 Matrix 1st Row 1st Column 2nd Row 1st Col
natali 33 [55]

Answer:

\left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

Step-by-step explanation:

The matrix system for the linear equations: x + 2y = 8, 2x + 6y = 9

\left[\begin{array}{ccc}1&2&\\2&6\\\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}8\\9\end{array}\right]

To get the coefficient of x and y, the inverse of the first matrix (let the first matrix be A) must be known.

A^{-1} = (1 / determinant of A) x Adjoint of A

the determinant of A = (1 x 6) - (2 x 2) = 6 - 4 = 2

Adjoint of A = \left[\begin{array}{ccc}6&-2&\\-2&1\\\end{array}\right]

A^{-1}= \frac{1}{2} \left[\begin{array}{ccc}6&-2\\-2&1\end{array}\right] = \left[\begin{array}{ccc}3&-1&\\-1&1/2\\\end{array}\right]

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Find an equation for the tangent to the curve at the given point y=x^3 , (2,8)
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\bf y=x^3\implies \left. \cfrac{dy}{dx}=3x^2 \right|_{x=2}\implies \stackrel{\stackrel{m}{\downarrow }}{12} \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{2}~,~\stackrel{y_1}{8})~\hspace{10em} slope = m\implies 12 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-8=12(x-2) \\\\\\ y-8=12x-24\implies y=12x-16

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Someone help me on this
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Answer:

idk

Step-by-step explanation:

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