Let the amount invested with 5% interest be x
Therefore, the amount invested with 6% interest will be (6000-x)
It is given that the total interest earned yearly is $337.5. Thus, the equation of interest will be:
Multiplying both sides by 100 we get:
Subtracting both sides by 36000 we get:
Thus, the amount invested at 5% is $2250
Therefore, the amount invested at 6% will be $(6000-2250)=$3750
The first equation, 8x - 9y = - 23
Obtain the equation in slope- intercept form
y = mx + c ( m is the slope and c the y-intercept )
to calculate m use the gradient formula
m = ( y₂ - y₁ ) / ( x₂ - x₁ )
with (x₁, y₁ ) = ( , 3) and (x₂, y₂ ) = (- 4, - 1 )
m = = (- 4)/-
=
partial equation is y = x + c
to find c substitute either of the 2 points into the partial equation
using (- 4, - 1 ), then
- 1 = - + c ⇒ c =
y = x +
← in slope- intercept form
the equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
rearrange the slope- intercept equation into this form
multiply through by 9
9y = 8x + 23 ( subtract 9y and 23 from both sides )
8x - 9y = - 23 in standard form
Answer:
Step-by-step explanation:
=> 5x-4+2(x-4) = 16
Expanding the brackets
=> 5x-4+2x-8 = 16
Combining like terms
=> 5x+2x-4-8 = 16
=> 7x - 12 = 16
Adding 12 to both sides
=> 7x = 16+12
=> 7x = 28
Dividing both sides by 7
=> x = 4