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Airida [17]
3 years ago
5

Can someone help me?

Mathematics
2 answers:
loris [4]3 years ago
4 0

Answer:

i do not know srry

Step-by-step explanation:

i think u should try and solve it with a better teacher

Maslowich3 years ago
3 0
1) 2123.7
2) 37.7
3) 9.4
4) 70.7
5) 136.1
6) 413.96
7) a) 1963.5
b) 5301.4
c) 3337.9

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Can someone please help me on this? thanks!!
tankabanditka [31]

Answer:

store C is the best with .122 per ounce the others are .129 and .135

6 0
3 years ago
A manager wants to select one group of 4 people from his 28 assistants.
Keith_Richards [23]

There are, 20475 different groups are possible if the manager wants to select one group of 4 people from his 28 assistants.

<h3>What is permutation and combination?</h3>

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

We have:

A manager wants to select one group of 4 people from his 28 assistants.

The total number of groups possible = C(28, 4)

= \rm \dfrac{28!}{4!(28-4)!}

After calculating:

= 20475

Thus, there are, 20475 different groups are possible if the manager wants to select one group of 4 people from his 28 assistants.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ1

8 0
2 years ago
The sum of two consecutive integers is 471.<br><br> what is the equation
Naddik [55]

Answer:

x+(x+1)=471

Step-by-step explanation:

6 0
3 years ago
A survey is made to determine the number of households having electric appliances in a certain city. It is found that 75% have r
Mashcka [7]

Answer:

The probability that a household has at least one of these appliances is 0.95

Step-by-step explanation:

Percentage of households having radios P(R) = 75% = 0.75

Percentage of households having electric irons P(I) = 65% = 0.65

Percentage of households having electric toasters P(T) = 55% = 0.55

Percentage of household having iron and radio P(I∩R) = 50% = 0.5

Percentage of household having radios and toasters P(R∩T) = 40% = 0.40

Percentage of household having iron and toasters P(I∩T) = 30% = 0.30

Percentage of household having all three P(I∩R∩T) = 20% = 0.20

Probability of households having at least one of the appliance can be calculated using the rule:

P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)

P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20  P(at least one of the three) = 0.95

The probability that a household has at least one of these appliances is 0.95

3 0
3 years ago
there are nickels, dimes, and quarters in a piggy bank. altogether, the coins are worth $3.65. the number of dimes is three time
hoa [83]

This question is solved using a system of equations, and doing this, we get that: There are 9 quarters, 4 nickels and 12 dimes.

I am going to say that:

x is the number of nickels.

y is the number of dimes.

z is the number of quarters.

In all, they are worth $3.65.

A nickel is worth $0.05, a dime is worth $0.1 and a quarter is worth $0.25, so:

0.05x + 0.1y + 0.25z = 3.65

Dimes: 3 times greater than nickels:

This means that:

y = 3x

Quarters: One greater than double the number of nickels:

This means that:

z = 2x + 1

Value of x:

We have y and z as function of x, so we can replace into the equation and find the value of x, so:

0.05x + 0.1y + 0.25z = 3.65

0.05x + 0.1(3x) + 0.25(2x+1) = 3.65

0.05x + 0.3x + 0.5x + 0.25 = 3.65

0.85x = 3.4

x = \frac{3.4}{0.85}

x = 4

y and z:

y = 3x = 3(4) = 12

z = 2x + 1 = 2(4) + 1 = 9

There are 9 quarters, 4 nickels and 12 dimes.

A similar question is found at brainly.com/question/17096268

4 0
3 years ago
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