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3 years ago

find the equation of the perpendicular bisector of the line segment joining the points (3,8) and (-5,6).

Mathematics

2 answers:

IgorLugansk [536]3 years ago

3 0

Answer:

y = - 4x + 3

Step-by-step explanation:

The perpendicular bisector is positioned at the midpoint of AB at right angles.

We require to find the midpoint and slope m of AB

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = A(3, 8) and (x₂, y₂ ) = B(- 5, 6)

m = $\frac{6-8}{-5-3}$ = $\frac{-2}{-8}$ = $\frac{1}{4}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{1}{4} }$ = - 4

mid point = [0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

Using the coordinates of A and B, then

midpoint AB = [0.5(3 - 5), 0.5(8 + 6) ] = (- 1, 7 )

Equation of perpendicular in slope- intercept form

y = mx + c ( m is the slope and c the y- intercept )

with m = - 4

y = - 4x + c ← is the partial equation

To find c substitute (- 1, 7) into the partial equation

Using (- 1, 7), then

7 = 4 + c ⇒ c = 7 - 4 = 3

y = - 4x + 3 ← equation of perpendicular bisector

Reil [10]3 years ago

3 0

Answer:

he perpendicular bisector is positioned at the midpoint of AB at right angles.

We require to find the midpoint and slope m of AB

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = A(3, 8) and (x₂, y₂ ) = B(- 5, 6)

m = = =

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - 4

mid point = [0.5(x₁ + x₂ ), 0.5(y₁ + y₂ ) ]

Using the coordinates of A and B, then

midpoint AB = [0.5(3 - 5), 0.5(8 + 6) ] = (- 1, 7 )

Equation of perpendicular in slope- intercept form

y = mx + c ( m is the slope and c the y- intercept )

with m = - 4

y = - 4x + c ← is the partial equation

To find c substitute (- 1, 7) into the partial equation

Using (- 1, 7), then

7 = 4 + c ⇒ c = 7 - 4 = 3

y = - 4x + 3 ← equation of perpendicular bisector

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3 years ago

Find the perimeter of the following shape, rounded to the nearest tenth:

Mademuasel [1]

Answer:

B, 19.1

Step-by-step explanation:

Imagine that each side is the hypotenuse of a triangle. You want to use the Pythagorean theorem on each of these triangles to find the length of the side.

Let's start with AB:

One side of the triangle is the distance between the points in the x direction only. A is at the x-coordinate of -3 while B is at the x-coordinate of 2. The side is, thus, 5 units.

The other side of the triangle is the distance between the points in the y direction only. A is at the y-coordinate of 5, while B is at 6. The distance is 1 unit.

So we have a triangle with the base of 5 and the height of 1. The Pythagorean theorem says:

Base² + Height² = Hypotenuse²

a² + b² = c²

where a, b are the sides, and c is the hypotenuse.

Put our values into this, the base is 5 and the height is 1:

5² + 1² = c²

25 + 1 = 26 = c²

c = √26 ≈ 5.1

Repeat this for the lengths BC, CD, and DA.

x-difference = 2

y-difference = 4

4² + 2² = c²

20 = c²

c = √20 ≈ 4.47

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y-difference = 1

(since this is the same as AB we can use that value ≈ 5.1 )

x-difference = 2

y-difference = 4

(since this is the same as BC, we can use that value ≈ 4.47)

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2 years ago

find the equation of the perpendicular bisector of the line segment joining the points (3,8) and (-5,6).​

find the equation of the perpendicular bisector of the line segment joining the points (3,8) and (-5,6).