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wolverine [178]
3 years ago
15

The box plot show the price of textbooks at a local high school. What range describe the middle 50% if the price (p) of the text

books?
Mathematics
1 answer:
Grace [21]3 years ago
3 0

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as the box plot is not attached.

However, the interpretation of the question is to determine the inter-quartile range (IQR) ; this represents the middle 50% of scores

To answer this question, I will make use of the attached box plot.

IQR is calculated as:

IQR = Q_3 - Q_1

Q_1 and Q_3 are represented by the vertical edges of the rectangle in the box plot. [See attachment]

Reading Q_1 and Q_3, we have:

Q_1 = 37

Q_3 = 50

The IQR is:

IQR = 50 - 37

IQR = 13

<em>Hence, the range that describes the middle 50% of the attached plot is 13</em>

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Simplify.<br><br> 2x5 - 6x2 + 4x4y<br> -------------------------<br> 2x
Ede4ka [16]
We have the rational expression \frac{2x^{5}-6x^{2}+4x4y}{2x}; to simplify it, we are going to try to find a common factor in the numerator, and, if we are luckily, that common factor will get rid of the denominator 2x.
Notice that in the denominator all the numbers are divisible by two, so 2 is part of our common factor; also, all the terms have the variable x, and the least exponent of that variable is 1, so x will be the other part of our common factor. Lets put the two parts of our common factor together to get 2x.
Now that we have our common factor, we can rewrite our numerator as follows:
\frac{2x(x^{5}-6x+2(2y)}{2x}
We are luckily, we have 2x in both numerator and denominator, so we can cancel those out:
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4 0
3 years ago
The body temperatures of adults have a mean of 98.6°F and a standard deviation of 0.60° F. Describe the center and variability o
amid [387]

Answer:

center = 98.6, variability = 0.08

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

The center is the mean.

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The standard deviation of the sample of 50 adults is the variability, so

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7 0
3 years ago
The perimeter of a rectangular painting is 310 centimeters. If the width of the painting is 56 centim
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Answer:

The length is 99 cm

Step-by-step explanation:

The perimeter of a rectangle is

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Divide each side by 2

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155 = l+56

Subtract 56

155-56 = l+56-56

99 = l

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