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nataly862011 [7]
3 years ago
12

How many liters of a 40% sugar solution must be mixed with 30 liters of a 60% sugar solution to make a 56 % sugar solution?

Mathematics
2 answers:
julia-pushkina [17]3 years ago
6 0

Answer

7.5 liters

Step-by-step explanation:

We need to make an equation.

40%, x liters

60%, 30 liters

=56%

0.40(x) + 0.60 (30) = 0.56 (x + 30)

0.40x + 18 = 0.56x + 16.8

18 - 16.8 = 0.56x - 0.40x

1.2 = 0.16x

7.5 = x

If this is correct, listen and stan BLACKPINK and BTS!!

konstantin123 [22]3 years ago
5 0

Answer:

7.5 liters of a 40% sugar solution

Step-by-step explanation:

Let

x ----> liters of a 40% sugar solution

Remember that

40\%=40/100=0.40\\60\%=60/100=0.60\\56\%=56/100=0.56

we know that

The amount of liters of a 40% sugar solution (x) multiplied by 0.40 plus the amount of liters of a 60% sugar solution (30 L) multiplied by 0.60 must be equal to the total amount of liters mixed (x+30) multiplied by 0.56

0.40x+0.60(30)=0.56(x+30)

solve for x

0.40x+18=0.56x+16.8\\0.56x-0.40x=18-16.8\\0.16x=1.2\\x=7.5\ L

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The difference of 28 and a number m is 3
jonny [76]

Answer:

28 - m = 3

28 - 3 = m

25 = m

Hope this helps :) mark me brainliest if you want to

8 0
2 years ago
A random sample of 25 ACME employees showed the average number of vacation days taken during the year is 18.3 days with a standa
Norma-Jean [14]

Answer:

a) Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

b) df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

c) Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

Step-by-step explanation:

Data given and notation  

\bar X=18.3 represent the sample mean

s=3.72 represent the sample standard deviation

n=25 sample size  

\mu_o =15 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

Part a: State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean for vacation days is higher than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Part b: P-value  and conclusion

The first step is calculate the degrees of freedom, on this case:  

df=n-1=25-1=24  

For this case the p value is given p_v = 0.0392

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the true mean is higher than 15 at 5% of signficance.  

Part c

Type I error, also known as a “false positive” is the error of rejecting a null  hypothesis when it is actually true. Can be interpreted as the error of no reject an  alternative hypothesis when the results can be  attributed not to the reality.

So for this case a type I of error would be reject the hypothesis that the true mean is less or equal than 15 and is actually true.

3 0
3 years ago
The number of hours a lightbulb burns before failing varies from bulb to bulb. The population distribution of burnout times is s
liubo4ka [24]

ANSWER:

The average burnout time of a large number of bulbs has a sampling distribution that is close to Normal.

STEP-BY-STEP EXPLANATION:

The cental limit theorem states, that id the sample size is large (30 or more), then the sampling distribution of the sample means is approximately normal with mean ц and standar deviation б/\sqrt{n}

Thus the correct answer is the average burnout time of a large number of bulbs has a sampling distribution that is close to Normal.

6 0
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A cuboid measures 6cm by 3cm by 2cm<br><br> Draw a net of the cuboid
Tresset [83]

Answer:

See attachment for cube

Step-by-step explanation:

Given

Length = 6cm

Width = 3cm

Height = 2cm

Required

The net of the cuboid

A cuboid has 6 faces.

The dimension of these faces are:

Length and Width; Length and Height;

Length and Width; Length and Height;

Width and Height; Width and Height;

This means that the faces will have the following dimensions:

6cm by 3cm; 6cm by 2cm

6cm by 3cm; 6cm by 2cm

3cm by 2cm; 3cm by 2 cm

Taking into account the above measurements and dimensions, you draw 6 faces, then join similar sides lengths.

<em>See attachment for net of the cuboid</em>

4 0
3 years ago
What is X I need help i dont know how to do this
Anit [1.1K]

Answer:

x = 75

Step-by-step explanation:

Triangle BDH

The angle must add to 180 degrees

36+ 39 + DHB = 180

75 + DHB = 180

DBH = 180-75

DHB = 105

DBH + x = 180 since it is a straight line

105+ x = 180

x = 75

6 0
3 years ago
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