How many liters of a 40% sugar solution must be mixed with 30 liters of a 60% sugar solution to make a 56 % sugar solution?

Mathematics

2 answers:

julia-pushkina [17]2 years ago

6 0

Answer

7.5 liters

Step-by-step explanation:

We need to make an equation.

40%, x liters

60%, 30 liters

=56%

0.40(x) + 0.60 (30) = 0.56 (x + 30)

0.40x + 18 = 0.56x + 16.8

18 - 16.8 = 0.56x - 0.40x

1.2 = 0.16x

7.5 = x

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konstantin123 [22]2 years ago

5 0

Answer:

7.5 liters of a 40% sugar solution

Step-by-step explanation:

Let

x ----> liters of a 40% sugar solution

Remember that

$40\%=40/100=0.40\\60\%=60/100=0.60\\56\%=56/100=0.56$

we know that

The amount of liters of a 40% sugar solution (x) multiplied by 0.40 plus the amount of liters of a 60% sugar solution (30 L) multiplied by 0.60 must be equal to the total amount of liters mixed (x+30) multiplied by 0.56

$0.40x+0.60(30)=0.56(x+30)$

solve for x

$0.40x+18=0.56x+16.8\\0.56x-0.40x=18-16.8\\0.16x=1.2\\x=7.5\ L$

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Select the equation with the solution x = 25. The equation should have the variable on both sides, a decimal coefficient on the

Katyanochek1 [597]

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7 0

2 years ago

Please help ASAP failing class if i dont answer correct

NNADVOKAT [17]

(See the imagine for reference)
Let’s solve where they have a triangle, so the height is 9 cm, the base is 3 cm:

1/2 • 9 • 3 = 13.5

Since there’s 2 triangles we do:

13.5(2) = 27

Now the rectangle in the middle, where the height is 9cm and the base is 12cm:

12 • 9 = 108

Add up the areas:

108 + 27 = 135