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PtichkaEL [24]
2 years ago
11

If (x - 4) varies inversely as (y + 3) and x = 8 when y = 2, what is x when y = - 1?

Mathematics
1 answer:
denpristay [2]2 years ago
3 0

Answer:

x=14

Step-by-step explanation:

If two values are inversely proportional, their product must be maintained. That way, if one value goes up, the other goes down by the same extent.

Therefore, if (x-4) and (y+3) vary inversely, their product will be the same for all values of x-4 and y+3.

Let x=8 and y=2 as given in the problem. Substitute values:

(8-4)(2+3)=(4)(5)=20

Hence, the maintained product is 20.

Thus, we have the following equation:

(x-4)(y+3)=20

Substitute y=-1 to find the value of x when y=-1:

(x-4)(-1+3)=20,\\(x-4)(2)=20,\\x-4=10,\\x=10+4=\boxed{14}

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===============

6x - 5y = 3

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============= -

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