Given:
The system Mx+Ny=P has a solution (1,3) where Rx+Sy=T; <span>M, N, P, R,S and T are non-zero real numbers.
Solve for M, N, R, P, S, T:
M +3N = P
R + 3S = T
The given choices should simplify to the equations above.
A) Mx +Ny = P
7Rx + 7Sy = 7T
7(Rx + Sy) = 7T
Rx + Sy = T
remarks: CORRECT
B) (M+R)x + (N+S)y = P + T
Rx + Sy = T
Mx + Rx + Ny + Sy = P + T
Mx + Ny + T = P + T
Mx + Ny = P
remarks: CORRECT
C) Mx + Ny = P
(2M - R)x + (2N - S)y = P - 2T
2Mx - Rx + 2Ny - Sy = P - 2T
2(Mx + Ny) - (Rx + Sy) = P - 2T
2P - (Rx + Sy) = P - 2T
remarks: INCORRECT
</span>
Answer:
(D) and nice work with me in both of this ok meaning made by my lines
Answer:
D
Step-by-step explanation:
You have to solve the compound inequality 
The absolute value 
means the distance from the number b to the origin. Thus, the inequlity 
has as solutions all numbers b that are at the distance from the origin greater than 6.
So, 
Answer:
448 R50
Step-by-step explanation:
