Speed = Distance/Time. Let speed be V, distance D and time T
a)Given: D₁ =45km, V₁=x km/h
V₁=D₁/T
V₁=45/T OR T= 45/V₁
b) Given : D₂ =48 km and V₂ = V₁ + 4 km/h
V₂ = 48/T, but V₂ = V₁+4, then:
V₁+4 = 48/T OR T=48/(V₁+4). Since Time is same, then we can write:
45/V₁ =48/(V₁+4), solve for V₁:
45V₁ + 180 = 48V₁
3V₁ =180 and V₁ = x = 60 km/h
In the year 1998, movie tickets will be greater than $5.50 as determined by solving the equation y=4.25[(1.035)^x].
What is an equation?
- Math can be used to analyze an equation or a set of equations.
- An equation is a sentence that maintains the equivalence of two expressions. Most of the time, it is easy to solve the arithmetic equations given in an exact manner.
- While perfect solutions can occasionally be found, it is more typical to find approaches that are just as accurate. It speaks to the particular guidelines for quadratic mathematical equations.
A movie ticket cost $4.25 in 1990.
The inflation rate is about 3.5%
Rate increased ,r=100%+3.5%=103.5%=1.035
equation generated is,
y=4.25[(1.035)^x]
Solving the equation for each year, we get the following data:
Tabulating the data
Year cost
1990 4.25
1991 ....
.... ....
1998 5.5964~ 5.6
In the year 1998, the will be greater than $5.50.
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Answer:
30,000
Step-by-step explanation:
5,000 in 6 months therefore 10,000 in one year and 30,000 in 3 years
