All categories

3 years ago

HELP ASAP PLEASE!!!

Mathematics

2 answers:

xenn [34]3 years ago

4 0

Answer:

E. None of these

Step-by-step explanation:

Points: (11, -4), (13, -7)

slope = m = (y2 - y1)/(x2 - x1) = (-7 - (-4))/(13 - 11) = (-7 + 4)/2 = -3/2

y - y1 = m(x - x1)

y - (-4) = (-3/2)(x - 11)

y + 4 = (-3/2)x + 33/2

y + 8/2 = (-3/2)x + 33/2

y = (-3/2)x + 25/2

Answer: E. None of these

tekilochka [14]3 years ago

3 0

Step-by-step explanation:

A(11,-4) B(13,-7)

x1 y1 x2 y2

y=mx+c

-4=11m+c -(i) -7=13m+c -(ii)

Subtract equation (ii) from (i)

-7=13m+c

-4=11m+c

+ - -

-3=2m

2m=-3

m=-3/2

put m=-3/2 in equation (ii)

-7=13*(-3/2)+c

c=-7+39/2

c=(-14+39)/2

c=15/2

y=mx+c

y=-3/2x+15/2

y=(-3x+15)/2

2y=-3x+15

2y+3x-15=0

You might be interested in

What is the vertex of the function f(x) = 12 + 3x + ?

goldfiish [28.3K]

Answer:

(2,1)

Explanation: f(x)=3x^(2)-12x+13

a=3

h=2

k=1

6 0

3 years ago

Choose as many answers as apply.

Pie

Answer:

b,c,d

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Which graph represents (x - 1)2/9 (y-3)2/1

Marat540 [252]

We can only see one graph here

7 0

3 years ago

Read 2 more answers

Water is leaking out of an inverted conical tank at a rate of 6800.0 cubic centimeters per min at the same time that water is be

m_a_m_a [10]

Answer:

6.82 $mt^3/min$

Step-by-step explanation:

By congruence of triangles, the radius r of the cone base when its height is 1 meter satisfies the relation

r/1 = 2.5/6

(See picture attached)

So, r = 0.4166 meters when the water is 1 meter high.

The volume of a cone with radius of the base = R is given by

$V=\frac{\pi R^2h}{3}$

So, the volume of water when it is 1 meter high is

$V=\frac{\pi* 0.(4166)^2}{3}=0.1817\;mt^3$

One minute later, the height of the water is 1 meter + 30 centimeters = 1.30 mt

The radius now satisfies

r/1.3 = 2.5/6

and now the radius of the base is

r = 0.5416 mt

and the new volume of water is $0.3071\;mt^3$

So, the water is raising at a speed of

0.3071-0.1871 = 0.12 $mt^3/min$

This speed equals the difference between the water being pumped and the water leaking,

So,

<em>0.12 = Speed of water being pumped -6.8 </em>

and

Speed of water being pumped = 6.8+0.12 = 6.82 $mt^3/min$

8 0

3 years ago

Hello, i am having a hard time solving this. If anyone can please explain how to solve it in order for me to solve future questi

lora16 [44]

Answer:

Step-by-step explanation:

7 0

2 years ago