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Mathematics

2 answers:

xenn [34]3 years ago

4 0

Answer:

E. None of these

Step-by-step explanation:

Points: (11, -4), (13, -7)

slope = m = (y2 - y1)/(x2 - x1) = (-7 - (-4))/(13 - 11) = (-7 + 4)/2 = -3/2

y - y1 = m(x - x1)

y - (-4) = (-3/2)(x - 11)

y + 4 = (-3/2)x + 33/2

y + 8/2 = (-3/2)x + 33/2

y = (-3/2)x + 25/2

Answer: E. None of these

tekilochka [14]3 years ago

3 0

Step-by-step explanation:

A(11,-4) B(13,-7)

x1 y1 x2 y2

y=mx+c

-4=11m+c -(i) -7=13m+c -(ii)

Subtract equation (ii) from (i)

-7=13m+c

-4=11m+c

+ - -

-3=2m

2m=-3

m=-3/2

put m=-3/2 in equation (ii)

-7=13*(-3/2)+c

c=-7+39/2

c=(-14+39)/2

c=15/2

y=mx+c

y=-3/2x+15/2

y=(-3x+15)/2

2y=-3x+15

2y+3x-15=0

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Find the coordinate that divides the directed line segment from A(-2,-4) to B(8,1) in the ratio of 2 to 3

zalisa [80]

We have that
A(-2,-4) B(8,1) 

let
M-------> the coordinate that divides the directed line segment from A to B in the ratio of 2 to 3

we know that

A--------------M----------------------B
2 3
distance AM is equal to (2/5) AB
distance MB is equal to (3/5) AB
so

step 1
find the x coordinate of point M
Mx=Ax+(2/5)*dABx
where
Mx is the x coordinate of point M
Ax is the x coordinate of point A
dABx is the distance AB in the x coordinate
Ax=-2
dABx=(8+2)=10
Mx=-2+(2/5)*10-----> Mx=2

step 2
find the y coordinate of point M
My=Ay+(2/5)*dABy
where
My is the y coordinate of point M
Ay is the y coordinate of point A
dABy is the distance AB in the y coordinate
Ay=-4
dABy=(1+4)=5
Mx=-4+(2/5)*5-----> My=-2

the coordinates of point M is (2,-2)

see the attached figure