Ok, here we go:
5 cars total.
1. Rachel - first car in line, yellow, SUV
2. blue car (Rachel is in front of the blue car), convertible, Anton
3. minivan - third car in line, Diego
4. white car, sedan, Ingrid
5. green car, immediately behind white car, Yuna, pickup
We know that Rachel is first, a blue car is second and the minivan is third. We know that 3, 4 cannot be a convertible since one is a minivan and the other is a sedan. We also know that a yellow car is in front of the convertible.
Based off of that we know that car 5 cannot be a convertible since 4 is white and not yellow. So 1 or 2 is the convertible and SUV. But we know that Rachel is in front of a blue car and the yellow car is in front of a convertible so that makes car #2 the blue convertible and car #1 the yellow SUV.
Fill in what you do know and start to eliminate the outliers. Hope that helps.
Answer: 0.001 or 1/1000
Since it is a negative exponent and -3 so it is in the thousandths, so 1/1000 or 0.001.
Have a good day! : )
Answer:
50h+6
Step-by-step explanation:
50h+ (150/25) <--- Divide/ simplify
=50h+6
Hello!
The answer are:
- Product of powers.
- Power of a power.
- Negative exponents.
<h2>Why?</h2>
Let's solve it!
It's a math rule that we must solve first what's into a brake or parenthesis, so,
First: Product of powers ![[(7)^{5}*(7)^{3}]](https://tex.z-dn.net/?f=%5B%287%29%5E%7B5%7D%2A%287%29%5E%7B3%7D%5D)
According to the exponent's law, we have a product of powers case, so, we need to sum the exponents and keep the base
Exponents: 5 and 3
Base: 7
Applying it we have:
Then,
We have a power of a power case, which involves multiplying the exponents:
![[(7)^{5}*(7)^{3}]^{-4}](https://tex.z-dn.net/?f=%5B%287%29%5E%7B5%7D%2A%287%29%5E%7B3%7D%5D%5E%7B-4%7D)
Exponents: 3 and -4
Then,
Finally, we can apply the negative exponents, the negative exponent's rules state that negative exponents are the reciprocal of the positive exponents,
So, we will have that:
Have a nice day!
