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valkas [14]
3 years ago
6

Mr Frank purchased 5_1/4 pounds of rocks. He used 3/5 of a pound on one aquarium. He then split the rest of the rocks between hi

s three remaining aquariums. How many rocks will be in one aquarium?​
Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
6 0

Answer:

1_11/20 pounds, or 1.55 pounds.

Step-by-step explanation:

Since at the beginning, he had 5 1/4 pounds and used 3/5, we subtract the amount of pounds. We are then left with 93/20 pounds, which he then splits among 3 containers. Dividing by three, we then get 31/20 pounds in one aquarium, or 1 11/20 pounds in each aquarium or 1.55 pounds.

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A farm lets you pick 3 pints of raspberries for 12.00 what is the price per pint/
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Answer:

$4

Step-by-step explanation:

I tried to make it as simple as possible.

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A delivery person uses a service elevator to bring boxes of books up to an office. The delivery person weighs 180 lb and each bo
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3 years ago
What’s this question
yKpoI14uk [10]
<h3>Hm ok, so the correct answer here would be (0,3) and heres why:</h3>

If the y would be equal to 0, everything would then just depend if you add or subtract the x:

y-x=-3\\\\y+x=3\\\\y= 0\\x=3\\\\then:\\\\0-3=3\\and\\0+3=3

Now the first answer could be correct for:

y-x=-3\\because\ if\\\\y=-3 \ and \ x=0 \ then\\-3-0=-3

However, this answer is not correct for the other equation. the same true for all the other answers except (0,3)

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8 0
3 years ago
A lottery consists of one $2000 winner, three $500 winners, and ten $100 winners. a total of 1000 tickets are sold for $10 each.
Semenov [28]

Answer: -5.5

 

WOKINGS

Given that the lottery has the following number of winners:

One $2000 winner

Three $500 winners

Ten $100 winners

 

Also Given,

A total of 1000 tickets are sold

Each ticket costs $10

 

The expected winning for a person purchasing one ticket is the sum of the products of the gain/loss and their corresponding probability.

 

There is one $2000 winner

There are 1000 tickets

The probability of winning $2000

= 1/1000

= .001

There are three $500 winners

There are 1000 tickets

The probability of winning $500

= 3/1000

= .003

 


There are ten $100 winners

There are 1000 tickets

The probability of winning $100

= 10/1000

= .01

 

Since each ticket costs $10

Everyone who buys a ticket automatically loses $10.

Therefore, the probability of losing $10 is 1

 

Now to calculate the expected winning for a person purchasing one ticket

= 2000(.001) + 500(.003) + 100(.01) – 10(1)

= 2 + 1.5 + 1 – 10

= -5.5

 

The expected winning is -5.5. This implies that a person playing this lottery can expect to lose $5.50 for every one ticket that they purchase. 

7 0
3 years ago
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