Answer:
I would help but this question is hard lol
Step-by-step explanation:
Variance is the average of the square of the differences of each data with the mean. To calculate for the variance, we first calculate for the mean. Then, we subtract each data with the mean. Next, each difference would be squared and added. The resulting value would be divided on how many data are used. We calculate as follows:
Mean = <span>9 + 7 + 6.5 </span>+ 7.5 + 7 + 8 + 5 + 6 + 7.5 + 8 / 10
Mean = 6.4
Squared of the sum of the differences = (9-6.4)^2 + (7-6.4)^2 + (6.5-6.4)^2 + (7.5-6.4)^2 + (7-6.4)^2 + (8-6.4)^2 + (5-6.4)^2 + (6-6.4)^2 + (7.5-6.4)^2 + (8-6.4)^2 = 17.15
Variance = 17.15 / 10 = 1.715
Because 3×5=15 and it will work both ways
Answer:
see below
Step-by-step explanation: 7 1 16 33
y = x² translated t the point (3, 2) y = 0 when x = 0
y = (x - 3)² moves the function three units to the right y = 0 when x = -3
y = (x-3)² + 2 moves the function up 2 units y = 2 when x = -3
y = (x-3)² + 2
y = x² - 6x + 9 + 2
y = x² - 6x +11
graph the equations x², (x-3)² + 2, and x² - 6x + 11 to verify (I did)
Answer:
At least 18 students scored below a 67.
Step-by-step explanation:
Given the 5 number summary of scores obtained by 37 students in a test worth 100 points :
55, 67, 73, 81, 98
Minimum = 55
Q1 = 67
Q2 = 73
Q3 = 81
Maximum = 98
Q1 = first quartile = 25%
Atleast 25 % scored below 67 (True)
25% of 37 students = 0.25 * 37 = 9.25
Atleast 9 students scored below 67 (True)
Median, Q2 = 50%
Score between Q2 and Q1 = 50% - 25% = 25% ;
Hence, atleast 25 students scored between 73 and 67 ; meaning (0.25 *37) = 9.25 students Hence. Atleast, 9 students scored between 73 and 67 (True)
Third quartile = 75%
Percentage above third quarterile = (100 - 75)% = 25%
Hence, atleast 25% scored above 81 (True)
The false statement is At least 18 students scored below a 67.