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Annette [7]
2 years ago
8

Anybody want points?

Mathematics
2 answers:
nordsb [41]2 years ago
7 0
I do. but i also feel as it is okay to fail . i need some but it also feels like i don’t . hope thag helped
il63 [147K]2 years ago
6 0
It’s Critiquect on my alt, cause KATIE keeps on deleting literally everything I post. It’s literally so annoying omg

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Suppose that 75% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou
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Answer:

b) 0.2961

c) 0.2251

d) Mean = 11.25, Standard deviation =  1.667  

Step-by-step explanation:

We are given the following information:

We treat trucks undergoing a brake inspection passin as a success.

P( trucks undergoing a brake inspection passes the test) = 75% = 0.75

a) Conditions for binomial probability distribution

  1. There are n independent trial.
  2. Each trial have a success probability p
  3. The probability of success is same for all trials.

Then the number of trucks undergoing a brake inspection follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 15

b) P(proportion of groups will between 8 and 10 trucks pass the inspection)

We have to evaluate:

P(8\leq x \leq 10) = P(x = 8) + P(x = 9) + P(x = 10)\\= \binom{15}{8}(0.75)^8(1-0.75)^7 + \binom{15}{9}(0.75)^9(1-0.75)^6 + \binom{15}{10}(0.75)^{10}(1-0.75)^5\\= 0.0393 + 0.0917 + 0.1651\\= 0.2961

c) P( exactly 3 trucks fail the inspection)

p = 0.25

P(x = 3)\\= \binom{15}{3}(0.25)^3(1-0.25)^{12}\\=0.2251

d) Mean and standard deviation

\mu = np = 15(0.75) = 11.25\\\sigma = \sqrt{np(1-p)} = \sqrt{15(0.75)(1-0.75)} = 1.667

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You make a dessert with lemon gelatin and lime gelatin. What percent of the dessert is lime-flavored? Explain
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A cookie company packages its cookies in rectangular prism boxes designed with square bases that have both a length and width of
maw [93]

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h³- 8h² + 16h

Step-by-step explanation:

The problem tells us that the length and width of these boxes are both 4 inches less than the height of the box.

So if we name <u>h the height of the box</u>, the <u>width of the box would be h - 4 </u>and the <u>height of the box would be h - 4.</u>

Now, the volume  of a rectangular prism is given by V = height x width x length

So, considering the values we have in this problem we get:

V= height x width x volume

V = h (h-4)(h-4)

V= h(h-4)²

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