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2 years ago

Which is a counterexample for the conditional statement shown?

Mathematics

1 answer:

ziro4ka [17]2 years ago

8 0

Answer: the points from a line

Step-by-step explanation:

I just did the test

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The residents of a city voted on whether to raise property taxes. The ratio of yes votes to no votes were 6 to 5. If there were

Natasha_Volkova [10]

3020

Step-by-step explanation:

ans.

Total ratio of votes=6+5

=11

1 ratio of votes=6644÷11

=604

Ratio of no votes=5

Number of no votes=Ratio of no votes×1 ratio of no votes

=604×5

3020

8 0

3 years ago

Shelly bought 7 boxes of fish food and 2 packets of cat food. Each box of fish food contained 6 pouches, and each packet of cat

AfilCa [17]

Answer: 34 more pouches

7 boxes - fish food; 1 box contained 6 pouches

Total amount of fish food is 7 × 6 = 42 pouches of fish food

2 packets - cat food; 1 packet contained 4 pouches

Total amount of cat food is 2 × 4 = 8 pouches

How many more pouches of fish food than cat food did Shelly buy?

42 pouches - 8 pouches = 34 pouches

Therefore there was 34 more pouches of fish food than cat food

7 0

2 years ago

2(4x – 3) ≥ –3(3x) + 5x?Which number line represents the solution set for the inequality 2x – 6 ≥ 6(x – 2) + 8?

nika2105 [10]

Answer:

x<=-1/2

Step-by-step explanation:

An inequality is a mathematical relationship that compares two unequal numbers using the number line

To solve the inequality 2x – 6 ≥ 6(x – 2) + 8

We first simplify both sides of the inequality

2x-6≥6x-12+8

2x-6≥6x-4

Add 6 to both sides

2x≥6x+2

-4x≥2

x≥2/-4

Sign changes when we divide both sides of equation by a negative sign

x<=-1/2

Therefore x is less than or equal to -1/2 on the number line

5 0

2 years ago

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

Answer:

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

Solution:

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

2 years ago

In the middle of the page draw an equilateral triangle with 2 inch sides and the bottom parallel to the bottom of the page. From

rewona [7]

Answer: the arrow is pointing 45° to the South of the West

See the picture attached to learn the procedure and the result.

7 0

3 years ago

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