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mote1985 [20]
2 years ago
8

Which of the following is true?

Mathematics
1 answer:
Dahasolnce [82]2 years ago
3 0

Answer:

the right ones are a c and d maybe

Step-by-step explanation:

these are probably wrong but I need my points so figure it out.

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I'll do your Home work Just post the questions

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2 x <img src="https://tex.z-dn.net/?f=%5Csqrt%7B36%7D" id="TexFormula1" title="\sqrt{36}" alt="\sqrt{36}" align="absmiddle" clas
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A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

  P(X < 1.33) = P( \frac{X -\mu}{\sigma} < \frac{1.33 -1.3}{0.01} ) = P(Z < 3) = 0.99865

  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

                                                                                            = 0.00135

 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

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Step-by-step explanation:

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Use a normal approximation to find the probability of the indicated number of voters. In this case, assume that 104 eligible vot
crimeas [40]

Answer:

The probability that exactly 27 of 104 eligible voters voted is​ 0.057 = 5.7%.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this case, assume that 104 eligible voters aged 18-24 are randomly selected.

This means that n = 104.

Suppose a previous study showed that among eligible voters aged 18-24, 22% of them voted.

This means that p = 0.22

Mean and standard deviation:

\mu = 104*0.22 = 22.88

\sigma = \sqrt{104*0.22*0.78} = 4.2245

Probability that exactly 27 voted

By continuity continuity, 27 consists of values between 26.5 and 27.5, which means that this probability is the p-value of Z when X = 27.5 subtracted by the p-value of Z when X = 26.5.

X = 27.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{27.5 - 22.88}{4.2245}

Z = 1.09

Z = 1.09 has a p-value of 0.8621

X = 26.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{26.5 - 22.88}{4.2245}

Z = 0.86

Z = 0.86 has a p-value of 0.8051

0.8621 - 0.8051 = 0.057

The probability that exactly 27 of 104 eligible voters voted is​ 0.057 = 5.7%.

5 0
3 years ago
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