All categories

3 years ago

HELP ASAP PLEASE

Mathematics

2 answers:

Oxana [17]3 years ago

6 0

The figure 1 i think you can used to find the volume

kherson [118]3 years ago

5 0

Answer:

option 1

Step-by-step explanation:

$volume \ of \ cone = \frac{1}{3} \pi r^2 h \\r = 4\\h = 8\\so, volume = \frac{1}{3} \pi (4^2)( 8)$

You might be interested in

the factors of the following polynomial are given below.choose the right factors that correspond to each given polynomial and wr

seraphim [82]

$\\ \ast\rm\longmapsto (x-9)(x+9)$

$\\ \ast\rm\longmapsto x^2-9^2$

$\\ \ast\rm\longmapsto x^2-81$

$\\ \ast\rm\longmapsto (2x-7)(2x+7)$

$\\ \ast\rm\longmapsto 2x^2-7^2$

$\\ \ast\rm\longmapsto 4x^2-49$

$\\ \ast\rm\longmapsto (4x-9y)(4x+9y)$

$\\ \ast\rm\longmapsto 4x^2-9y^2$

$\\ \ast\rm\longmapsto 16x^2-81y^2$

$\\ \ast\rm\longmapsto (5x-1)(5x+1)$

$\\ \ast\rm\longmapsto 5x^2-1^2$

$\\ \ast\rm\longmapsto 25x^2-1$

$\\ \ast\rm\longmapsto (9x-20y^2)(9x+20y^2)$

$\\ \ast\rm\longmapsto 9x^2-(20y^2)^2$

$\\ \ast\rm\longmapsto 81x^2-400y^2$

6 0

3 years ago

Two- thirds of a number added to itself is 20. what is the number?

MrRissso [65]

Equation

Let the number = x

(2/3)x + x = 20 Change the x to thirds.

(2/3)x + 3/3x = 20 3/3 = 1 Now combine the like terms.

(2 + 3)/3 = 20 2/3 + 3/3 = 5/3

(5/3) x = 20 Multiply both sides by 3/5

(5/3)*(3/5)x = 20*3/5 Complete the multiplication on the right

x = 4 * 3 Combine

x = 12 Answer

3 0

3 years ago

Read 2 more answers

What are the measures of those two angles? I’ll mark brainliest!

Lelechka [254]

Answer:

Two angles of a quadrilateral : 220 and 90 deg.

The other two angles (x and y) are in ratio 2:3.

We have:

x + y = 360 - 220 - 90 = 50 (property of sum of 4 angles in quadrilateral)

x/y = 2/3 => x = 2y/3

=>2y/3 + y = 50

=> 5y/3 =50

=> 5y = 150

=> y = 30

=> x = 2 x 30/3 = 20

=> Two other angles are 20 and 30 deg

Hope this helps!

8 0

3 years ago

A page should have perimeter of 42 inches. The printing area within the page

Tamiku [17]

Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .

<u>Step-by-step explanation:</u>

We have , A page should have perimeter of 42 inches. The printing area within the page would be determined by top and bottom margins of 1 inch from each side, and the left and right margins of 1.5 inches from each side. let's assume width of the page be x inches and its length be y inches So,

Perimeter = 42 inches

⇒ $2(x+y) = 42\\x+y = 21\\y = 21-x$

width of printed area = x-3 & length of printed area = y-2:

area = $length(width)$

$area = (x-3)(y-2)\\area = (x-3)(21-x-2)\\area = (x-3)(19-x)\\area = -x^{2} + 22x -57$

Let's find $\frac{d(area)}{dx}$ :

$\frac{d(area)}{dx}$ = $\frac{d(-x^{2}+22x-57)}{dx} = -2x +22$ , for area to be maximum $\frac{d(area)}{dx}$ = 0

⇒ $-2x+22 = 0\\2x =22\\x=11 inches$

And ,

$y = 21-x\\y = 21-11\\y = 10 inches$

∴ Overall dimensions of the page in order to maximize the printing area is page should be 11 inches wide and 10 inches long .

7 0

3 years ago

For each ordered pair determine wheatear it is a solution to 2x

stealth61 [152]

All you have to do is plug in the x and y values for each ordered pair into the left hand side of the equation and see if you get 15 = 15. If you do, the ordered pair is a solution; otherwise it is not a solution. For example, let's try (-2,-3); that is x = -2 and y = -3:

2x - 9y = 15
2(-2) - 9(-3) = 15
-4 - (-27) = 15
-4 + 27 = 15
23 = 15

This is obviously not true, so (-2,-3) is not a solution. Now you try it on each of the ordered pairs given in the problem statement.

3 0

3 years ago