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3 years ago

HELP ASAP PLEASE

Mathematics

2 answers:

Oxana [17]3 years ago

6 0

The figure 1 i think you can used to find the volume

kherson [118]3 years ago

5 0

Answer:

option 1

Step-by-step explanation:

$volume \ of \ cone = \frac{1}{3} \pi r^2 h \\r = 4\\h = 8\\so, volume = \frac{1}{3} \pi (4^2)( 8)$

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Pam spelled 68 of 100 words correctly on the pretest how Many words dos the Miss? If she learns 8 of those each day how long wil

solmaris [256]

It would take 4 days

5 0

4 years ago

(-6,1) after a translation of (x-2y)

zysi [14]

Answer:

(-8,1)

Step-by-step explanation:

Imma assume you meant (x-2, y)

x coordinate becomes -6-2=-8

y coordinate stays the same

so the image is (-8,1)

5 0

2 years ago

Algebra 2 help please ASAP

Burka [1]

Answer:

The option A,D and E are correct.

Step-by-step explanation:

Given: 2x^3-250x^2

Factor : 2x^2(x-125)

So, GCF = 2x^2

Now a = 1 and b= 5

we know that a^3-b^3 = (a-b)(a^2+ab+b^2)

(x)^3 - (5)^3 = (x-5)(x^2+5x+25)

So, the option A,D and E are correct.

3 0

3 years ago

Solve by quadratic formula:<br> 3x^2 - 10x - 20= 0

Arlecino [84]

this is your answer, i hope this helps you

5 0

3 years ago

For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at

GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

$\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}$ $\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}$

Now, let's add the components of the same direction:

$\begin{gathered} V_x=W_x+A_x=35.35+0=35.35\\ \\ V_y=W_y+A_y=35.35-540=-504.65 \end{gathered}$

To find the resultant bearing (theta), we can use the formula below:

$\begin{gathered} \theta=\tan^{-1}(\frac{V_y}{V_x})\\ \\ \theta=\tan^{-1}(\frac{-504.65}{35.35})\\ \\ \theta=-86° \end{gathered}$

The angle -86° is equivalent to -86 + 360 = 274°.

Therefore the correct option is b.

8 0

1 year ago