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Lady bird [3.3K]
2 years ago
13

Jack shoots a rocket upward from the ground. the height of the rocket is modeled by (x-2)^2=25. the time after launch is represe

nted by x.
a. how high will the rocket reach?
b. at what time will the rocket reach its highest point?
c. at what time will the rocket be back on the ground?​

Mathematics
1 answer:
Snezhnost [94]2 years ago
3 0

Using a quadratic function, we have that:

a) The rocket reaches a maximum height of 25 units.

b) The rocket reaches it's highest point after 2 seconds.

c) The rocket will be back on the ground after 7 seconds.

<h3>What is the equation of a parabola given it’s vertex?</h3>

The equation of a quadratic function, of vertex (h,k), is given by:

y = a(x - h)² + k

In which a is the leading coefficient.

For this problem, placing it in vertex form, the equation for the height h is given by:

h = -(x - 2)² + 25.

Hence the vertex is (2,25), which means that:

a) The rocket reaches a maximum height of 25 units.

b) The rocket reaches it's highest point after 2 seconds.

The rocket hits the ground when h = 0, hence:

-(x - 2)² + 25 = 0

(x - 2)² = 25

Applying the square root to both sides:

x - 2 = 5.

x = 7.

The rocket will be back on the ground after 7 seconds.

More can be learned about quadratic functions at brainly.com/question/24737967

#SPJ1

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19

Step-by-step explanation:

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3 years ago
Find three consctive postive integers such that the prodect of the median integer and the largest integer is 72
Tcecarenko [31]

Answer: 7,8,9

Step-by-step explanation:

Let the numbers be a, a+1 and a+2. Therefore, based on the question, this will be:

= (a + 1)(a + 2) = 72

a² + 2a + a + 2 = 72

a² + 3a + 2 - 72 = a

a² + 3a - 70 = 0

a² + 10a - 7a - 70 = 0

a(a + 10) - 7(a + 10)

a - 7 = 0

a = 7

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a + 1 = 7+1 = 8

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8 0
2 years ago
What is 107-44=10+23+__
Anon25 [30]
The answer will be 33
4 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!!PLZ HELP!!!
Andrei [34K]

Answer:

Step-by-step explanation:

Hello,

<em>"Ray says the third-degree polynomial has four intercepts. Kelsey argues the function can have as many as three zeros only."</em>

We know that Kelsey is right, a polynomial of degree 3 has maximum 3 zeroes, so it means that the graph of this polynomial has maximum 3 x-intercepts.

<u>So how Ray can be right too?</u>

we need to think of y-intercept, if we add the y-intercept then Ray can be right too,

as you can see in one example below

there are 3 x-intercepts and 1 y-intercept.

This being said, Ray is not always right. For instance x^3

has only 1 zero (multiplicity 3) its graph has only 1 intercept in the point (0,0)

hope this helps

6 0
3 years ago
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
3 years ago
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