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2 years ago

Let A = {10, 20, 30, 40, 50, 60} and B = {10, 40, 60}. What is A ∩ B?

Mathematics

2 answers:

erastovalidia [21]2 years ago

5 0

This means common members {10,40,60}

sergiy2304 [10]2 years ago

4 0

Answer:

The A ∩ B is {10, 40 ,60} .

Step-by-step explanation:

As given in the question

A = {10, 20, 30, 40, 50, 60}

B = {10, 40, 60}

The intersection A ∩ B of two sets A and B is represented the set that contains all elements of A that also belong to B .

Thus the A ∩ B becomes

A ∩ B = {10, 40 ,60}

Therefore the A ∩ B is {10, 40 ,60} .

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First look for the fundamental solutions by solving the homogeneous version of the ODE:

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(You could include a constant term <em>f</em> here, but it would get absorbed by the first solution $C_1$ anyway.)

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$e^{-3t}$ is already accounted for, so assume an ansatz of the form

$y_p=(at^3+bt^2+ct)e^{-3t}$

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Substitute into the ODE:

$(9at^3+(9b-18a)t^2+(9c-12b+6a)t+2b-6c)e^{-3t}+3(-3at^3+(3a-3b)t^2+(2b-3c)t+c)e^{-3t}=t^2e^{-3t}$

$9at^3+(9b-18a)t^2+(9c-12b+6a)t+2b-6c-9at^3+(9a-9b)t^2+(6b-9c)t+3c=t^2$

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