Answer:
![g(x)=-2\sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%3D-2%5Csqrt%5B3%5Dx)
or

Step-by-step explanation:
Given
![f(x) = \sqrt[3]x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Csqrt%5B3%5Dx)
Required
Write a rule for g(x)
See attachment for grid
From the attachment, we have:


We can represent g(x) as:

So, we have:
![g(x) = n * \sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%20%3D%20n%20%2A%20%5Csqrt%5B3%5Dx)
For:

![2 = n * \sqrt[3]{-1}](https://tex.z-dn.net/?f=2%20%3D%20n%20%2A%20%5Csqrt%5B3%5D%7B-1%7D)
This gives:

Solve for n


To confirm this value of n, we make use of:

So, we have:
![-2 = n * \sqrt[3]1](https://tex.z-dn.net/?f=-2%20%3D%20n%20%2A%20%5Csqrt%5B3%5D1)
This gives:

Solve for n


Hence:
![g(x) = n * \sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%20%3D%20n%20%2A%20%5Csqrt%5B3%5Dx)
![g(x)=-2\sqrt[3]x](https://tex.z-dn.net/?f=g%28x%29%3D-2%5Csqrt%5B3%5Dx)
or:

Answer:
wouldn't that just be -35?
Step-by-step explanation:
you just have to do -29-6
Answer:
Step-by-step explanation:
Given that prices for a pair of shoes lie in the interval
[80,180] dollars.
Delivery fee 20% of price.
i.e. delivery fee will be in the interval [4, 9]
(1/20th of price)
Total cost= price of shoedelivery cost
Hence f(c) = c+c/20 = 21c/20
The domain of this function would be c lying between 80 to 180
So domain =[80,180]
---------------------------------
Amount to be repaid = 42 dollars
Once he received this amount, the price would be
105+42 =147
But since price range is only [21*80/20, 21*180/20]
=[84, 189]
Since now Albert has 147 dollars, he can afford is
[80,147]
Answer:
3000miles
Step-by-step explanation:
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