Answer:
<em>The Hydrostatic force is =7800N</em>
Step-by-step explanation:
<em>Let recall the following,</em>
<em>
The hydrostatic force is a force that occurs when a force resulting from pressure of a body or fluid at rest
</em>
<em>The hydrostatic force is the pressure at the center x the area
</em>
<em>The Pressure is = density x gravity x height
</em>
<em>The acceleration due to gravity = 9.8m^2
</em>
<em>
The weight of the water (density) = 1000 kg/m3
</em>
<em>
So find the mass at the center which is,
</em>
<em>
√(4)/2 that is below the water level
</em>
<em>
The hydrostatic force is = (√(4)/2m) (1000 kg/m^3 x 9.8m/s) ((1/2)(4)(4√(4)/2)m^2)
</em>
<em>
Therefore, in expressing the hydrostatic force against one side of the plate is.
</em>
<em>
(√(4)/2m) (1000 kg/m^3 x 9.8m/s) ((1/2)(4)(4√(4)/2)m^2) =7800N
</em>
<em>
The Hydrostatic force =7800N
</em>