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Mrac [35]
3 years ago
14

Help its really easy but i need help.Which calculation would result in the decimal point moving two spaces to the right in a dec

imal number?
The decimal number is divided by 100.

The decimal number is multiplied by 10.

The decimal number is multiplied by 100.

The decimal number is divided by 10.
Mathematics
2 answers:
Oksanka [162]3 years ago
6 0

Answer:

easy the number is multiplied by 100

Step-by-step explanation:

aliya0001 [1]3 years ago
5 0

Answer:

The decimal number is multiplied by 100

Step-by-step explanation:

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she has more of a percdntage of the chocalate bar taken away. whil only sam has 75 grams eaten elizabeth has a more percentage.

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it would be 10 soccer balls

Step-by-step explanation:

10 every week if it was constant (because they could've sold more one week then less the next) but the genuine answer is 10 soccer balls :)

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Solve the following by using mathematical Induction. For &gt;/ 1
cluponka [151]

Answer:

See explanation

Step-by-step explanation:

Prove that

1^2+2^2+3^3+...+n^2=\dfrac{1}{6}n(n+1)(2n+1)

1. When n=1, we have

  • in left part 1^2=1;
  • in right part \dfrac{1}{6}\cdot 1\cdot (1+1)\cdot (2\cdot 1+1)=\dfrac{1}{6}\cdot 1\cdot 2\cdot 3=1.

2. Assume that for all k following equality is true

1^2+2^2+3^3+...+k^2=\dfrac{1}{6}k(k+1)(2k+1)

3. Prove that for k+1 the following equality is true too.

1^2+2^2+3^3+...+(k+1)^2=\dfrac{1}{6}(k+1)((k+1)+1)(2(k+1)+1)

Consider left part:

1^2+2^2+3^2+...+(k+1)^2=\\ \\=(1^2+2^2+3^3+...+k^2)+(k+1)^2=\\ \\=\dfrac{1}{6}k(k+1)(2k+1)+(k+1)^2=\\ \\=(k+1)\left(\dfrac{1}{6}k(2k+1)+k+1\right)=\\ \\=(k+1)\dfrac{2k^2+k+6k+6}{6}=\\ \\=(k+1)\dfrac{2k^2+7k+6}{6}=\\ \\=(k+1)\dfrac{2k^2+4k+3k+6}{6}=\\ \\=(k+1)\dfrac{2k(k+2)+3(k+2)}{6}=\\ \\=(k+1)\dfrac{(k+2)(2k+3)}{6}

Consider right part:

\dfrac{1}{6}(k+1)((k+1)+1)(2(k+1)+1)=\\ \\\dfrac{1}{6}(k+1)(k+2)(2k+3)

We get the same left and right parts, so the equality is true for k+1.

By mathematical induction, this equality is true for all n.

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