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Amanda [17]
2 years ago
10

Please help!! I don’t know how to solve this. Which one is the digit of the units in 3^81:

Mathematics
1 answer:
egoroff_w [7]2 years ago
3 0

<u>Solution:</u>

  • 3⁸¹ = 3⁹ ⁺ ⁹ ⁺ ⁹ ⁺ ⁹ ⁺ ⁹ ⁺ ⁹ ⁺ ⁹ ⁺ ⁹ ⁺ ⁹ ⁺ ⁹
  • 3⁸¹ = 3⁹ x 3⁹ x 3⁹ x 3⁹ x 3⁹ x 3⁹ x 3⁹ x 3⁹ x 3⁹
  • 3⁹ = 19683 <u>[Using Calculator]</u>

This means that the Unit digit of 19683 is 3. For each number, multiply the unit's digit of 3⁹.

  • 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3 x 3
  • => 19683
  • => <u>Unit digit of 3⁸¹ = 3</u>

Option A is correct.

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A segment has an endpoint at (1,−2). The midpoint is at (−4,−2). What are the coordinates of the other endpoint?
Ostrovityanka [42]

An easy way to find an endpoint when the midpoint is given is to simply count the distance from the given endpoint to the midpoint, and go that distance from the midpoint in the opposite direction of the other endpoint. Using your problem as an example:

The y value doesn't change, so we only need to worry about x.

From 1 to -4, you go left 5 (-4 - 1 = -5). So, do that again, and you get -9.

Therefore, the coordinates of the other endpoint are (-9, -2), or B.

<em>Hope this helps! :)</em>

6 0
3 years ago
The Turtle and Achilles compete. They start at the same time from the same place. Achilles runs at a speed of 13 mph while the T
grandymaker [24]

Answer:

2 minutes.  

Step-by-step explanation:

Let t be the time taken in competition and the distance covered by Achilles be x miles.

We have been given that when Achilles reaches the finish line, the Turtle is 2/5 of a mile behind him. This means that distance covered by turtle will be: x-\frac{2}{5}.

Achilles runs at a speed of 13 mph while the Turtle moves at a speed of 1 mph.

Since we know that \text{Time}=\frac{\text{Distance}}{\text{Speed}}, so we can set two equations for time taken by Achilles and turtle as:

t=\frac{x}{13}...(1)

t=\frac{(x-\frac{2}{5})}{1}...(2)

From equation (1) we will get,

x=13t

Upon substituting this value in equation (2) we will get,

t=\frac{13t-\frac{2}{5}}{1}    

Let us have a common denominator.  

t=\frac{\frac{65t-2}{5}}{1}

t=\frac{65t-2}{5}

Upon multiplying both sides of our equation by 5 we will get,

5t=5\times \frac{65t-2}{5}

5t=65t-2

5t-65t=65t-65t-2

-60t=-2

t=\frac{-2}{-60}

t=\frac{1}{30}

So, the competition took 1/30 hour, let us convert our given time in minutes.

\frac{1}{30}\text{ hour}\times \frac{60\text{ minutes}}{\text{hour}}

\frac{1}{30}\times 60\text{ minutes}

2\text{ minutes}  

Therefore, the competition took 2 minutes.


8 0
3 years ago
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777dan777 [17]

Answer:

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cos 120° is in Quadrant II.  cos 120° = --------------- = ---------

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8 0
3 years ago
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Alexxx [7]
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7 0
3 years ago
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laiz [17]

Answer:

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Step-by-step explanation:

Plug in X and Y, verify accuracy

7 0
4 years ago
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