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ira [324]
3 years ago
10

Write in expanded form 3 ways 23.56

Mathematics
1 answer:
AveGali [126]3 years ago
4 0

Answer:

23+ .5 + .06

20+3+.56

10+10+ 3.56

Step-by-step explanation:

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one batch of cookies makes 24 cookies. the recipe calls for 1 3/4 cups of flour. if Sarah needs to make 60 cookies how much flou
Svetllana [295]

Answer:

4 3/8 cups of flour needed for 60 cookies

Explanation:

You can multiply 24 by 2.5 to get 60 so you'd multiply the cups of flour by 2.5 as well. You multiply both of them by the same number because it's a ratio. You'd multiply then simplify to get the answer 4 3/8 cups of flour.

7 0
3 years ago
❤️❤️help please ASAP
Archy [21]
From what i see, i guess the answer may be B. it looks like it, but i dont really know.
6 0
3 years ago
Read 2 more answers
I need help with this problem ASAP!
JulijaS [17]

Answer:

aye down load the app Socratic

Step-by-step explanation:

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6 0
2 years ago
PLEASE HELP!!!!!!!!<br> a2 - 10ab + 3b^2
Zielflug [23.3K]
Let's simplify step-by-step.

<span><span><span>a2</span>−<span><span>10a</span>b</span></span>+<span>3<span>b2

</span></span></span>There are no like terms.

Answer:

<span>=<span><span><span>a2</span>−<span><span>10a</span>b</span></span>+<span>3<span>b<span>2</span></span></span></span></span>
5 0
3 years ago
Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4
arsen [322]

we are given

R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k

now, we can find x , y and z components

x=cos(8t),y=sin(8t),z=8ln(cos(t))

Arc length calculation:

we can use formula

L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt

x'=-8sin(8t),y=8cos(8t),z=-8tan(t)

now, we can plug these values

L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt

now, we can simplify it

L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8sec(t) dt

now, we can solve integral

\int \:8\sec \left(t\right)dt

=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|

now, we can plug bounds

and we get

=8\ln \left(\sqrt{2}+1\right)-0

so,

L=8\ln \left(1+\sqrt{2}\right)..............Answer

5 0
2 years ago
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