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3 years ago

13

What is the slope between the following problems?(8,-4) and (2,-4)

2 answers:

Varvara68 [4.7K]3 years ago

7 0

Answer:

Slope = 0/-6

(Sorry for the bad handwriting)

Lapatulllka [165]3 years ago

7 0

First, you will need to subtract your Y1 for your Y2. In this case your Y2 will be -4 and your Y1 is also -4. -4 minus -4 equals 0. This will be your numerator of your fraction to divide at the end. Now you need to subtract your X1 from your X2. Your X2 will be 2 and your X1 will be 8. 2 minus 8 equals -6. This will be your denominator. Finally, you will divide 0 by -6. This equals 0. Therefore, your slope is 0.

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Answer:

The equivalent expression to the givan expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Step-by-step explanation:

Given expression is 4th root of 324m^12 * the cubed root of 64k^9

The given expression can be written as

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

To find the equivalent expression to the given expression :

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}$

$=\sqrt[4]{81\times 4m^{12}}\times\sqrt[3]{16\times 4k^9}$

$=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}$

$=\sqrt[4]{3\times 3\times 3\times 3\times 4m^{12}}\times\sqrt[3]{4\times 4\times 4k^9}$

$=(3\times \sqrt[4]{m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4m^{12}})\times (4\times \sqrt[3]{k^9})$

$=(3\times \sqrt[4]{4}\times (m^{12})^{\frac{1}{4}})\times (4\times {(k^9)^{\frac{1}{3}})$

$=(3\sqrt[4]{4}\times m^{\frac{12}{4}})\times (4\times k^{\frac{9}{3}})$

$=(3\sqrt[4]{4}\times m^3)\times (4\times k^3)$

$=3\sqrt[4]{4}m^3.4k^3$

$=12\sqrt[4]{4}m^3k^3$

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

Therefore the equivalent expression to the given expression is

$\sqrt[4]{324m^{12}}\times\sqrt[3]{64k^9}=12\sqrt[4]{4}m^3k^3$

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