the tree is 24 years old. The inner part of the stem of the tree has a part referred to as cambium. Each year cambium produces high number of cells with thin cell walls when tree is highly active. These cells form the light-colored rings. When tree is less active cambium synthesizes few small cells with thick walls. The region occupied by these cells appear as a darker ring on the cross section of the stem. These two processes occur in the same year and as result each growth year is characterized by a ring consisting of a light and dark parts.
Answer:
this study is clearly an observational work
Explanation:
experimental studies involve to establish direct associations between a traits and its phenotypic effects. For example, a classical experimental study would involve to map a nonsense mutation in the ACTN3 gene significantly correlated to the non-sprinting phenotype
I believe group of cells working together and or performing the same task can be categorized also as a specialized tissue.
☁️Answer☁️
The answer is A. Its organism one because if it got its energy from a biotic source, there would be an arrow pointing towards it.
A certain bacterial mRNA is known to represent only one gene and to contain about 800 nucleotides. If you assume that the average amino acid residue contributes 110 to the peptide molecular weight, the largest polypeptide that this mRNA could code for would have a molecular weight of about _______.
A) 800.
B) 5,000.
C) 30,000.
D) 80,000.
E) An upper limit cannot be determined from the data given
Answer:
c. 30,000
Explanation:
The gene has a total of 800 nucleotides and would be transcribed into an mRNA having about 800 nucleotides. The nucleotides of mRNA are read in the form of genetic triplets. This means that the mRNA with 800 nucleotides would have about 800/3= 266.66 or 266 genetic codes. This mRNA would be translated into a polypeptide chain having around 266 amino acids.
One amino acid contributes 110 to the molecular weight. The total molecular weight of the largest possible polypeptide that can be encoded by the said gene would b 266 x 110= 29260 (around 30,000).
