We are given the functions:
f(x) = 4 x – 5 --->
1
g(x) = 3 x + 7 --->
2
To find for the value of f(x) + g(x), all we have to do is
to add equations 1 and 2:
f(x) + g(x) = 4 x – 5 + 3 x + 7
f(x) + g(x) = 7 x + 2 = y
In this case, for any real number value assign to x, we get
a real number value of y. This is because the function is linear.
Therefore the domain of the function is all real numbers.
Because
therefore
f(x) = (x-3)(2x² + 10x - 1) + k, where k = constant.
Because f(3) = 4, therefore k =4.
The polynomial is
f(x) = 2x³ + 10x² - x - 6x² - 30x + 3 + 4
= 2x³ + 4x² - 31x + 7
Answer: f(x) = 2x³ + 4x² - 31x + 7
<h3>Answer: C) none of the equations are identities</h3>
If you plugged theta = 0 into the first equation, then you would have
sin(45) + cos(45) = sin(0) + cos(0)
sqrt(2) = 1
which is a false equation. We don't have an identity here.
The same story happens with the second equation. Plug in theta = 0 and it becomes
cos(60) - sin(60) = cos^2(0) + tan(0)
1/2 - sqrt(3)/2 = 1 + 0
-0.37 = 1
which is false.
The total to this would be $1,389.93 because $1,299 + 7% = $1,389.93
