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Vlada [557]
3 years ago
13

A total of

Mathematics
1 answer:
LuckyWell [14K]3 years ago
4 0
If we make a an integer that represents the adults that bought tickets, and s the number of students, then we have the equations a+s=682, and a=68+s. 

Using the second equation, we find that s=a-68, so we plug this value of s into the first equation to get a+(a-68)=682. We simplify to find 2a=750. We divide by 2 to isolate the desired variable to get a=\boxed{375\text{ adult tickets were sold}}. 
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Draw a number line model to determine -9 + (-2)
belka [17]
The answer would be -11
6 0
3 years ago
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A sphere with a radical of 8.5cm
jek_recluse [69]
Take the common denominator and divide by 3
5 0
3 years ago
Last year, there were 148 pies baked for the bake sale. This year, there were c pies baked. Using c, write an expression for the
solniwko [45]

\huge{\boxed{c+148}}

We need to find the number of pies baked in years 1 and 2.

There were 148 pies baked in year 1. 148

There were c pies baked in year 2. 148+c

Rearrange the terms so the variable is first. c+148

5 0
3 years ago
Read 2 more answers
The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did
Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

P(A \, and \, B)= P(A)\times  P(B\left |  \right A )

From the options, we have;

P(fatigue \left |  \right drug) = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)×P(fatigue \left |  \right drug)  

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

4 0
3 years ago
The Farmer Supply is building storage building for fertilizer shaped top. The that has cylindrica base and cone county laws say
creativ13 [48]

Assuming  ℎ1 = 11 feet and ℎ 2 = 3 feet, the storage of the facility is going to be 603 cubic feet, which is more than 576 cubic feet

The diameter of the building has been given as 8cm

radius = d/2 = 8/2 = 4

Maximum height = h1 + h2 = 14

Find the volume of the fertilizer that is containeed in both of the trucks

2(12x4x6) = 576 feet

From the height of 14 feets we have to assume

h1 = 11 ft,

h2 = 3 ft

<h3>How to solve for volume</h3>

volume =\frac{1}{3} \pi r^{2} h2 + \pi r^{2} h1

= 0.333*3.14*4²*3 + 3.14*4²*11

= 602.8 ft ≈ 603

Read more on volume here: brainly.com/question/12410983

7 0
2 years ago
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