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VashaNatasha [74]
4 years ago
9

How do you solve 2 3/4 times 1 1/8 times 32

Mathematics
2 answers:
Yuri [45]4 years ago
7 0
2\frac{3}{4}\times1\frac{1}{8}\times32=\frac{2\times4+3}{4}\times\frac{1\times8+1}{8}\times\frac{32}{1}=(8+3)\times(8+1)\\\\=11\times9=\fbox{99}
NikAS [45]4 years ago
7 0
Multiplying fractions is always easier when you multiply impartial fractions.
2 3/4 = 11/4
1 1/8 = 9/8

Something that will make your life a lot easier is always to take advantage of the fact that you have whole numbers available (in this case the 32). You know that 4*1/4 = 1, and one times anything is itself and can be crossed out.
You can turn the 32 into 4*8, and use that 4 to multiple with 11/4 (or 11* 1/4) to get 11. Now you're left with:
11 * 9/8 * 8

Then 8 * 1/8 = 1 as well. So use the 8 you have remaining to multiple with 9/8 (or 9 * 1/8) to get 9. Now you're left with:
11 * 9.

11 * 9 = 99. 99 is your answer.
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