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Goryan [66]
2 years ago
5

Iodine-125 has a daily decay rate of about 1%. How many milligrams of a 500 mg sample will remain after 300 days? Round the answ

er to two decimal places. 0.60 mg 7.81 mg 24.52 mg 31.25 mg
Mathematics
2 answers:
Flauer [41]2 years ago
8 0

Answer:

24.52 mg will remain.

Step-by-step explanation:

Given,

The initial  quantity of Iodine-125  = 500 mg,

Also, it has a daily decay rate of about 1%.

Thus, the final quantity of Iodine-125 after x days,

A=500(1-\frac{1}{100})^x

=500(1-0.001)^x

=500(0.999)^x

For x = 300 days,

The remained quantity would be,

A=500(0.999)^{300}

=24.5204470356

\approx 24.52\text{ mg}

Third option is correct.

Amanda [17]2 years ago
7 0
So.. in this case, the starting amount is the 500mg sample... and the rate of decay, negative rate, is 1%, and at the time, the elapsed days is 0, to t = 0, P = 400

\bf \qquad \textit{Amount for Exponential change}\\\\
A=P(1\pm r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{starting amount}\to &500\\
r=rate\to 1\%\to \frac{1}{100}\to &0.01\\
t=\textit{elapsed period}\to &300\\
\end{cases}
\\\\\\
A=500(1-0.01)^{300}
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