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creativ13 [48]
3 years ago
10

First Link Services granted 20 million of its $1 par common shares to executives, subject to forfeiture if employment is termina

ted within five years. The common shares have a market price of $8 per share on the grant date of the restricted stock award. 1. Ignoring taxes, what is the total compensation cost pertaining to the restricted shares? 2. Ignoring taxes, what is the effect on earnings in the year after the shares are granted to executives?
Business
1 answer:
aivan3 [116]3 years ago
8 0

Answer:

(a).  $160 million

(b).  32 million  

Explanation:

According to the scenario, computation of the given data are as follows:-  

We can calculate the Total compensation cost pertaining to the restricted shares by using following formula:-

a). Total Compensation Cost Pertaining to the Restricted Shares = Common Share × Market Price Per Share

= 20 million × $8

= $160 million

B). Effect on Earnings in the Year After the Shares are Granted to Executives = Total Compensation Cost ÷ Terminated Year

= $160 million ÷ 5

= 32 million  

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stiks02 [169]

Answer:

Explanation:

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7 0
2 years ago
Which statement is false about liquidity?
BARSIC [14]

Answer:

Option D. Both A and B

Explanation:

The reason is that the investment that are readily convertible to cash are less risk and as a result the investors are compensated with lower returns and vice versa. So the only statement that is not false statement is option C and the statement A and B are False.

8 0
3 years ago
Milo Clothing experienced the following events during 2016, its first year of operation: 1. Acquired $12,000 cash from the issue
Serga [27]

Answer:

Explanation:

The four transactions  will be recorded in the general journal as follows:

1) Debit cash                 $12,000

             Credit common stock                       $12,000

(To record the sale of common stock)

2) Debit purchases                 $5,600

            Credit   cash                 $5,600

(To record purchase of inventory in cash)

3) Debit cash                 $5,712

           Credit sales                        $3,360

            Credit gross profit              $2,352

(To record the sale of inventory in cash)

4) Debit advertising expenses                   $650

          Credit cash                     $650

(To record the payment of advertising expenses in cash)

5 0
3 years ago
Mika decides to rent instead of buy because it is the cheapest option over the first 3 years. his move-in costs are one month's
Vika [28.1K]
Its "C" 828 i just took the test 
4 0
3 years ago
An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0
3 years ago
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