Answer:
-x+4
Step-by-step explanation:
x-2y
y= x-2
x-2(x-2)
x-2x+4
-x+4
So you do
distribute
a(b+c)=ab+ac
9(x+5)=9x+9 times 5=9x+45
7(x-3)=7x+7 times -3=7x-21
so now we have
9x+45+7x-21
group like terms
9x+7x+45-21
add
16x+24
simplified is 16x+24
Yes I agree with the last person, it’s Line D.
Answer:
The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.
Step-by-step explanation:
In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't. Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype. However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.
It is -1 because there is a negative one in front of the x.
